在python中打印到同一行而不是新行

这叫马车返回,或者 \r

使用

print i/len(some_list)*100," percent complete         \r",

逗号防止print添加换行符(空格将保持线与先前输出的距离)

另外,别忘了用 print "" 至少有一个定稿的新词!

在Python3.x中,您可以执行以下操作:

print('bla bla', end='')

(在Python2.6或2.7中也可以通过 from __future__ import print_function 在脚本/模块的顶部)

Python控制台progressbar示例:

import time

# status generator
def range_with_status(total):
    """ iterate from 0 to total and show progress in console """
    n=0
    while n<total:
        done = '#'*(n+1)
        todo = '-'*(total-n-1)
        s = '<{0}>'.format(done+todo)
        if not todo:
            s+='\n'        
        if n>0:
            s = '\r'+s
        print(s, end='')
        yield n
        n+=1

# example for use of status generator
for i in range_with_status(10):
    time.sleep(0.1)

对我来说,有效的是雷米和西利乌斯的答案:

from __future__ import print_function
import sys

print(str, end='\r')
sys.stdout.flush()

在python3.3+中,您不需要 sys.stdout.flush() . print(string, end='', flush=True) 作品。

所以呢

print('foo', end='')
print('\rbar', end='', flush=True)

将用bar覆盖foo。

您可能需要的控制台

sys.stdout.flush()

强制更新。我认为使用 , in print会阻止stdout刷新,而且不知何故它不会更新

游戏进行得太晚了-但是由于没有一个答案对我有效(我没有全部尝试),而且我在搜索中不止一次遇到这个答案。。。在python3中,这个解决方案非常优雅,我相信它完全符合作者的要求,它在同一行上更新了一条语句。请注意,如果线收缩而不是增长,则可能需要做一些特殊的操作(例如,可能使字符串具有固定长度,并在末尾填充空格)

if __name__ == '__main__':
    for i in range(100):
        print("", end=f"\rPercentComplete: {i} %")
        time.sleep(0.2)

这对我来说很有用,曾对它进行过一次黑客攻击,看看它是否可行,但从未在我的程序中实际使用过(GUI更好):

import time
f = '%4i %%'
len_to_clear = len(f)+1
clear = '\x08'* len_to_clear
print 'Progress in percent:'+' '*(len_to_clear),
for i in range(123):
    print clear+f % (i*100//123),
    time.sleep(0.4)
raw_input('\nDone')

import time
import sys


def update_pct(w_str):
    w_str = str(w_str)
    sys.stdout.write("\b" * len(w_str))
    sys.stdout.write(" " * len(w_str))
    sys.stdout.write("\b" * len(w_str))
    sys.stdout.write(w_str)
    sys.stdout.flush()

for pct in range(0, 101):
    update_pct("{n}%".format(n=str(pct)))
    time.sleep(0.1)

\b 将光标的位置移回一个空格
所以我们把它一直移到线的开头
然后我们写空格来清除当前行-当我们写空格时,光标向前/向右移动1
因此,在写入新数据之前,我们必须将光标移回行的开头

使用python2.7在Windows cmd上测试

到2020年底,linux控制台上的Python 3.8.5对我来说只起作用:

print('some string', end='\r')

贷方为: This post

试着这样做:

for i in some_list:
    #do a bunch of stuff.
    print i/len(some_list)*100," percent complete",

(结尾有逗号)

如果您使用的是Spyder,则这些行只需使用以前的所有解决方案连续打印即可。避免这种情况的方法是:

for i in range(1000):
    print('\r' + str(round(i/len(df)*100,1)) + '% complete', end='')
    sys.stdout.flush()

对于Python 3+

for i in range(5):
    print(str(i) + '\r', sep='', end ='', file = sys.stdout , flush = False)

基于 Remi answer 对于 Python 2.7+ 使用此选项:

from __future__ import print_function
import time

# status generator
def range_with_status(total):
    """ iterate from 0 to total and show progress in console """
    import sys
    n = 0
    while n < total:
        done = '#' * (n + 1)
        todo = '-' * (total - n - 1)
        s = '<{0}>'.format(done + todo)
        if not todo:
            s += '\n'
        if n > 0:
            s = '\r' + s
        print(s, end='\r')
        sys.stdout.flush()
        yield n
        n += 1


# example for use of status generator
for i in range_with_status(50):
    time.sleep(0.2)

为了 Python 3.6+ 对任何人来说 list 而不仅仅是 int s、 除了使用控制台窗口的整个宽度且不跨越新行外,您还可以使用以下选项:

注:请注意,该功能 get_console_with() 将只在基于Linux的系统上工作,因此您必须重写它才能在Windows上工作。

import os
import time

def get_console_width():
    """Returns the width of console.

    NOTE: The below implementation works only on Linux-based operating systems.
    If you wish to use it on another OS, please make sure to modify it appropriately.
    """
    return int(os.popen('stty size', 'r').read().split()[1])


def range_with_progress(list_of_elements):
    """Iterate through list with a progress bar shown in console."""

    # Get the total number of elements of the given list.
    total = len(list_of_elements)
    # Get the width of currently used console. Subtract 2 from the value for the
    # edge characters "[" and "]"
    max_width = get_console_width() - 2
    # Start iterating over the list.
    for index, element in enumerate(list_of_elements):
        # Compute how many characters should be printed as "done". It is simply
        # a percentage of work done multiplied by the width of the console. That
        # is: if we're on element 50 out of 100, that means we're 50% done, or
        # 0.5, and we should mark half of the entire console as "done".
        done = int(index / total * max_width)
        # Whatever is left, should be printed as "unfinished"
        remaining = max_width - done
        # Print to the console.
        print(f'[{done * "#"}{remaining * "."}]', end='\r')
        # yield the element to work with it
        yield element
    # Finally, print the full line. If you wish, you can also print whitespace
    # so that the progress bar disappears once you are done. In that case do not
    # forget to add the "end" parameter to print function.
    print(f'[{max_width * "#"}]')


if __name__ == '__main__':
    list_of_elements = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j']
    for e in range_with_progress(list_of_elements):
        time.sleep(0.2)

如果您使用的是Python3 这是给你的,真的很管用。

print(value , sep='',end ='', file = sys.stdout , flush = False)

只是我自己想出来的倒计时,但它也会工作的百分比。

import time
#Number of seconds to wait
i=15
#Until seconds has reached zero
while i > -1:
    #Ensure string overwrites the previous line by adding spaces at end
    print("\r{} seconds left.   ".format(i),end='')
        time.sleep(1)
        i-=1
    print("") #Adds newline after it's done

只要'/r'后面的字符串长度与前一个字符串相同或更长(包括空格),它就会在同一行上覆盖它。只需确保包含end='',否则它将打印成换行符。希望有帮助!

对于提供StartRunning()、StopRunning()的对象“pega”, boolean getIsRunning()和integer getProgress100()返回 值的范围为0到100,这提供了文本进度条 运行时。。。

now = time.time()
timeout = now + 30.0
last_progress = -1

pega.StartRunning()

while now < timeout and pega.getIsRunning():
    time.sleep(0.5)
    now = time.time()

    progress = pega.getTubProgress100()
    if progress != last_progress:
        print('\r'+'='*progress+'-'*(100-progress)+' ' + str(progress) + "% ", end='', flush=True)
        last_progress = progress

pega.StopRunning()

progress = pega.getTubProgress100()
print('\r'+'='*progress+'-'*(100-progress)+' ' + str(progress) + "% ", flush=True)

print('\r some string ', end='', flush=True)