比较和更新字典?

也许你在找这个:

result = [] 
for i,j in zip(dict1, dict2):
    i.update(j)
    result.append(i)

结果就是你想要的。

假设要合并两个同名dict,请尝试以下操作:

dict1 = [{'name':'Apple','lot':1234,'old_qty':100},{'name':'Grape','lot':456,'old_qty':20}]
dict2 = [{'name':'Apple','lot':1234,'new_qty':50},{'name':'Grape','lot':456,'new_qty':30}]

z = []
common_attr = 'name'
for d1 in dict1:
    for d2 in dict2:
        if d1[common_attr] == d2[common_attr]:
            z.append({**d1, **d2})
print(z)

希望这有帮助:)

伊荷,你可能在找这样的东西(考虑到钥匙的价值) name lot 可以从其他字典中唯一地标识字典):

dict1 = [{'name':'Apple','lot':1234,'old_qty':100},{'name':'Grape','lot':456,'old_qty':20}]
dict2 = [{'name':'Apple','lot':1234,'new_qty':50},{'name':'Grape','lot':456,'new_qty':30}]

dict3 = [d1 for d1 in dict1 for d2 in dict2 if d1["name"]==d2["name"] if d1["lot"]==d2["lot"] if not d1.update(d2)]

print(dict3)

只是一层一层的 for 循环

listc = lista[:] 

for i in listb:
    for j in listc:
        if i['name'] == j['name']:
            for x in i:
                if x not in j.keys():
                    j[x] = i[x]

print(listc)

(xenial)vash@localhost:~/python/stack_overflow$ python3.7 dicta_comp.py 
[{'name': 'Apple', 'lot': 1234, 'old_qty': 100, 'new_qty': 50}, {'name': 'Grape', 'lot': 456, 'old_qty': 20, 'new_qty': 30}]