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从具有条件的列表创建字典

if-statement dictionary list python

-2

4c74356b41 · 技术社区 · 7 年前

以下是我的资料:

ports = [ 1111, 2222, 3333 ]
keys = ['port', 'target_port', 'name']
ports = [dict.fromkeys(keys, port) for port in ports]

这产生:

[
    {
        "port": 1111,
        "target_port": 1111,
        "name": 1111
    }
    xxx
]

问题是,“name”的值必须是字符串。如何在列表理解中添加条件?

编辑:所有其他值必须保持整数
编辑:我目前的解决方法:

for port_dict in ports:
    port_dict['name'] = str(port_dict['port'])

最后使用的是被接受答案的倒数,这样我就可以在列表的末尾添加键:

keys = ['name', 'port', 'target_port']
ports = [{**dict.fromkeys(keys[1:], port), "name": str(port)}
         for port in ports]

4 回复 | 直到 7 年前

1

4

Dani Mesejo 7 年前

ports = [ 1111, 2222, 3333 ]
keys = ['port', 'target_port', 'name']

result = [{ **dict.fromkeys(keys[:2], port), "name" : str(port) } for port in ports]
print(result)

[{'target_port': 1111, 'name': '1111', 'port': 1111}, {'target_port': 2222, 'name': '2222', 'port': 2222}, {'target_port': 3333, 'name': '3333', 'port': 3333}]

2

3

Green Cloak Guy 7 年前

dict.fromkeys()

ports = [ {key: (str(port) if key == "name" else port) for key in keys}
          for port in ports]

3

1

r.ook jpp 7 年前

def force_str(val, key, str_keys):
    if key in str_keys:
        return str(val)
    else:
        return val

result = [{k: force_str(p, k, ['name']) for k in keys} for p in ports]

# [{'port': 1111, 'target_port': 1111, 'name': '1111'}, 
#  {'port': 2222, 'target_port': 2222, 'name': '2222'}, 
#  {'port': 3333, 'target_port': 3333, 'name': '3333'}]

str_keys key

4

0

user83543 7 年前

[{key: str(port) if key=="name" else port for key in keys} for port in ports]