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如何在没有星期日的情况下将日期和日期保存到单独的数组中?

php

0

Enthu · 技术社区 · 7 年前

$date = new DateTime("+ 1 day", new DateTimeZone('Asia/Thailand') );

for ($i=1; $i<=5; $i++) {
    $date->modify("+1 weekday");
    $delivery_dates[] = $date->format("m/d/Y");
    $delivery_days[] = $date->format("l, d F Y");
}

目前,我得到以下信息-

我使用了以下方法-

for ($i=1; $i<=5; $i++) {
    $date->modify("+1 weekday");
    if ($date->format("N") !== 7 {
       $delivery_dates[] = $date->format("m/d/Y");
       $delivery_days[] = $date->format("l, d F Y");
    }
}

上面的代码仍然显示在星期天。

2 回复 | 直到 7 年前

1

0

TsV 7 年前

    $from = '2018-10-10';
    $to = '2018-12-10';
    $start = new \DateTime($from);
    $end   = new \DateTime($to);
    $interval = \DateInterval::createFromDateString('1 day'); // 1 day === P1D, 5 month and 5 years === P5M5Y
    $period   = new \DatePeriod($start, $interval, $end); // A date period allows iteration over a set of dates and times, recurring at regular intervals, over a given period.
    // new \DatePeriod(10-10-2010, 5, 30-10-2010) ===> [10-10-2010, 15-10-2010, 20-10-2010, 25-10-2010, 30-10-2010]

    $result = [];

    foreach ($period as $day) {
        if (! in_array($day->format('w'), [0, 6])) { // check every date in period, ->format('w'): w - number of day; Monday = 1 or 7 (depends on wat day declared first)
            $result['date'][] = $day->format("m/d/Y");
            $result['day'][] = $day->format("l, d F Y");
        }
    }

2

0

k0pernikus 7 年前

假设您可以使用 Carbon ,一种实现方法是在while循环的帮助下生成范围,如果不是星期天,则只添加一个日期,同时确保获得所需的天数(在您的情况下为5天)。

/**
 * @param int $amount
 * @return Carbon[]
 */
public function getDeliveryDates($amount = 5): array
{
    $days = [];
    $current = Carbon::today();

    while (\count($days) < $amount) {
        $day = clone $current; // addDay works on instance, cloning it
        $day->addDay();
        $current = $day; // setting current to current day, so that it will iterate
        if ($current->isSunday()) {
            continue;
        }

        $days[] = $current;
    }

    return $days;
}

$formattedDates = [];
$formattedDays = [];
foreach (getDeliveryDates() as $date) {
    $formattedDates[] = $date->format('m/d/Y');
    $formattedDays[] = $date->format('l, d F Y');
}