我已经实现了一个小的IO类,它可以从不同磁盘上的多个和相同的文件中读取(例如,包含相同文件的两个硬盘)。在连续的情况下,两个磁盘在文件上的平均读取速度均为60MB/s,但是当我执行交错操作(例如,4K磁盘1,4K磁盘2然后合并)时,有效读取速度将降低到40MB/s而不是增加?
上下文:Win 7+JDK 7B70,2GB RAM,2.2GB测试文件。基本上,我尝试模仿Win7的ReadyBoost和RaidX,以一个穷人的方式。
在心脏中,当向类发出read()时,它会创建两个运行文件,其中包含从特定位置和长度读取预先打开的randomaccessfile的指令。使用执行器服务和future.get()调用,当两者都完成时,数据读取被复制到一个公共缓冲区并返回给调用方。
我的方法有概念错误吗?(例如,操作系统缓存机制将始终抵消?)
protected <T> List<T> waitForAll(List<Future<T>> futures)
throws MultiIOException {
MultiIOException mex = null;
int i = 0;
List<T> result = new ArrayList<T>(futures.size());
for (Future<T> f : futures) {
try {
result.add(f.get());
} catch (InterruptedException ex) {
if (mex == null) {
mex = new MultiIOException();
}
mex.exceptions.add(new ExceptionPair(metrics[i].file, ex));
} catch (ExecutionException ex) {
if (mex == null) {
mex = new MultiIOException();
}
mex.exceptions.add(new ExceptionPair(metrics[i].file, ex));
}
i++;
}
if (mex != null) {
throw mex;
}
return result;
}
public int read(long position, byte[] output, int start, int length)
throws IOException {
if (start < 0 || start + length > output.length) {
throw new IndexOutOfBoundsException(
String.format("start=%d, length=%d, output=%d",
start, length, output.length));
}
// compute the fragment sizes and positions
int result = 0;
final long[] positions = new long[metrics.length];
final int[] lengths = new int[metrics.length];
double speedSum = 0.0;
double maxValue = 0.0;
int maxIndex = 0;
for (int i = 0; i < metrics.length; i++) {
speedSum += metrics[i].readSpeed;
if (metrics[i].readSpeed > maxValue) {
maxValue = metrics[i].readSpeed;
maxIndex = i;
}
}
// adjust read lengths
int lengthSum = length;
for (int i = 0; i < metrics.length; i++) {
int len = (int)Math.ceil(length * metrics[i].readSpeed / speedSum);
lengths[i] = (len > lengthSum) ? lengthSum : len;
lengthSum -= lengths[i];
}
if (lengthSum > 0) {
lengths[maxIndex] += lengthSum;
}
// adjust read positions
long positionDelta = position;
for (int i = 0; i < metrics.length; i++) {
positions[i] = positionDelta;
positionDelta += (long)lengths[i];
}
List<Future<byte[]>> futures = new LinkedList<Future<byte[]>>();
// read in parallel
for (int i = 0; i < metrics.length; i++) {
final int j = i;
futures.add(exec.submit(new Callable<byte[]>() {
@Override
public byte[] call() throws Exception {
byte[] buffer = new byte[lengths[j]];
long t = System.nanoTime();
long t0 = t;
long currPos = metrics[j].handle.getFilePointer();
metrics[j].handle.seek(positions[j]);
t = System.nanoTime() - t;
metrics[j].seekTime = t * 1024.0 * 1024.0 /
Math.abs(currPos - positions[j]) / 1E9 ;
int c = metrics[j].handle.read(buffer);
t0 = System.nanoTime() - t0;
// adjust the read speed if we read something
if (c > 0) {
metrics[j].readSpeed = (alpha * c * 1E9 / t0 / 1024 / 1024
+ (1 - alpha) * metrics[j].readSpeed) ;
}
if (c < 0) {
return null;
} else
if (c == 0) {
return EMPTY_BYTE_ARRAY;
} else
if (c < buffer.length) {
return Arrays.copyOf(buffer, c);
}
return buffer;
}
}));
}
List<byte[]> data = waitForAll(futures);
boolean eof = true;
for (byte[] b : data) {
if (b != null && b.length > 0) {
System.arraycopy(b, 0, output, start + result, b.length);
result += b.length;
eof = false;
} else {
break; // the rest probably reached EOF
}
}
// if there was no data at all, we reached the end of file
if (eof) {
return -1;
}
sequentialPosition = position + (long)result;
// evaluate the fastest file to read
double maxSpeed = 0;
maxIndex = 0;
for (int i = 0; i < metrics.length; i++) {
if (metrics[i].readSpeed > maxSpeed) {
maxSpeed = metrics[i].readSpeed;
maxIndex = i;
}
}
fastest = metrics[maxIndex];
return result;
}
(metrics数组中的filemetrics包含读取速度的测量值,以自适应地确定各种输入通道的缓冲区大小-在我的测试中,alpha=0,read speed=1结果相等分布)
编辑
我运行了一个非纠缠测试(例如,在单独的线程中独立地读取两个文件),我的总有效速度为110MB/s。
编辑2
我想我知道为什么会这样。
当我以并行和顺序读取时,它不是磁盘的顺序读取,而是由于交错(并且可能会被分配表查找所困扰)而导致的读取-跳过-读取-跳过模式。这基本上将每个磁盘的有效读取速度降低到一半或更糟。