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删除多个表外键上的级联时删除

  •  1
  • Malick  · 技术社区  · 8 年前

    我有几个表具有外键约束,可以选择 ON DELETE CASCADE . 每个表都属于同一个名为 datasets .

    我可以使用以下方法检索完整的表列表:

    SELECT * 
    FROM INFORMATION_SCHEMA.TABLES 
    WHERE TABLE_SCHEMA ='datasets'
    

    对于每个表,我要删除 关于删除级联 名为的外键约束上的选项 FK_[TABLENAME]_SerieID 在哪里? [TABLENAME] 对应于表的名称(和 SerieId 是相同的外键。

    我能够对特定的表执行操作,例如 Table1 使用:

    ALTER TABLE  datasets.Table1
        DROP CONSTRAINT FK_Table1_SerieID
    
    ALTER TABLE datasets.Table1
        ADD CONSTRAINT FK_Table1_SerieID
            FOREIGN KEY (Serie_Id) REFERENCES[dbo].[Serie](SerieID)
            ON DELETE NO ACTION
    GO
    

    我要对属于架构的每个表执行上述操作 数据集 . 我对t-sql还不熟悉,不知道怎么做。

    我应该用光标吗?你能帮我做这个吗?

    我正在使用SQL Server 2016。

    1 回复  |  直到 8 年前
        1
  •  1
  •   Lukasz Szozda    8 年前

    我不会重新发明轮子。有个很好的剧本是由 Aaron Bertrand: Drop and Re-Create All Foreign Key Constraints in SQL Server .

    你可以很容易地扩展它来处理 NO ACTION 通过添加简单的 WHERE 限制:

    DECLARE @drop   NVARCHAR(MAX) = N'',
            @create NVARCHAR(MAX) = N'';
    
    -- drop is easy,just build a simple concatenated list from sys.foreign_keys:
    SELECT @drop += N'
    ALTER TABLE ' + QUOTENAME(cs.name) + '.' + QUOTENAME(ct.name) 
        + ' DROP CONSTRAINT ' + QUOTENAME(fk.name) + ';'
    FROM sys.foreign_keys AS fk
    INNER JOIN sys.tables AS ct
      ON fk.parent_object_id = ct.[object_id]
    INNER JOIN sys.schemas AS cs 
      ON ct.[schema_id] = cs.[schema_id]
    WHERE delete_referential_action_desc <> 'NO_ACTION'  -- here 
        AND cs.name = 'datasets';
    
    -- create is a little more complex. We need to generate the list of 
    -- columns on both sides of the constraint, even though in most cases
    -- there is only one column.
    SELECT @create += N'
    ALTER TABLE ' 
       + QUOTENAME(cs.name) + '.' + QUOTENAME(ct.name) 
       + ' ADD CONSTRAINT ' + QUOTENAME(fk.name) 
       + ' FOREIGN KEY (' + STUFF((SELECT ',' + QUOTENAME(c.name)
       -- get all the columns in the constraint table
        FROM sys.columns AS c 
        INNER JOIN sys.foreign_key_columns AS fkc 
        ON fkc.parent_column_id = c.column_id
        AND fkc.parent_object_id = c.[object_id]
        WHERE fkc.constraint_object_id = fk.[object_id]
        ORDER BY fkc.constraint_column_id 
        FOR XML PATH(N''), TYPE).value(N'.[1]', N'nvarchar(max)'),1,1,N'')
      + ') REFERENCES ' + QUOTENAME(rs.name) + '.' + QUOTENAME(rt.name)
      + '(' + STUFF((SELECT ',' + QUOTENAME(c.name)
       -- get all the referenced columns
        FROM sys.columns AS c 
        INNER JOIN sys.foreign_key_columns AS fkc 
        ON fkc.referenced_column_id = c.column_id
        AND fkc.referenced_object_id = c.[object_id]
        WHERE fkc.constraint_object_id = fk.[object_id]
        ORDER BY fkc.constraint_column_id 
        FOR XML PATH(N''), TYPE).value(N'.[1]', N'nvarchar(max)'),1,1,N'') + ');'
    FROM sys.foreign_keys AS fk
    INNER JOIN sys.tables AS rt -- referenced table
      ON fk.referenced_object_id = rt.[object_id]
    INNER JOIN sys.schemas AS rs 
      ON rt.[schema_id] = rs.[schema_id]
    INNER JOIN sys.tables AS ct -- constraint table
      ON fk.parent_object_id = ct.[object_id]
    INNER JOIN sys.schemas AS cs 
      ON ct.[schema_id] = cs.[schema_id]
    WHERE rt.is_ms_shipped = 0 AND ct.is_ms_shipped = 0
      AND delete_referential_action_desc <> 'NO_ACTION' -- here
      AND cs.name = 'datasets';
    print(@drop);
    print(@create);
    -- ...
    

    DBFiddle Demo


    一个警告!请避免添加 ORDER BY .

    此脚本使用

    SELECT @drop += N'...'
    <=>
    SELECT @drop = @drop + N'...'
    

    可能会产生不正确的结果。更多 nvarchar concatenation / index / nvarchar(max) inexplicable behavior