由于压缩的_对,纯虚拟结构和唯一_ptr的dll导入无法编译

我有两个项目,其中我的代码在一个项目中,作为一个dll导出,导入项目是一个测试项目。最后,我想要一个vtable,它可以导入到c中,并且只使用一个结构。

我的纯虚拟结构如下所示:

#ifdef DLL_EXPORTS
#define MyAPI  __declspec( dllexport )
#else DLL_EXPORTS
#define MyAPI  __declspec( dllimport  )
#endif DLL_EXPORTS

struct MyAPI IVirtual
{
    virtual int GetNumber() = 0;
    virtual ~IVirtual() = 0;
};

MyAPI IVirtual * IVirtual_New(int);
MyAPI void IVirtual_Delete(IVirtual *);

这有一个DLL的实现:

#include "Virtual.h"

struct Concrete : IVirtual
{
    int n;
    Concrete(int n) : n(n) { }
    virtual int GetNumber() { return n; }
    virtual ~Concrete() {}
};

IVirtual::~IVirtual() {}

MyAPI IVirtual * IVirtual_New(int n)
{
    auto that = new Concrete(n);
    return that;
}

MyAPI void IVirtual_Delete(IVirtual * that)
{
    auto fingerscrossed = static_cast<Concrete*>(that);
    delete fingerscrossed;
}

测试项目导入DLL。SharedPointer测试编译并确认断言。

#include "CppUnitTest.h"
#include <memory>
#include <MyDLL/Virtual.h>

using namespace Microsoft::VisualStudio::CppUnitTestFramework;

namespace UsageTest
{       
    TEST_CLASS(UsageTest)
    {
    public:
        TEST_METHOD(SharedConstructor)
        {
            //looks ok - tests pass
            std::shared_ptr<IVirtual> sptr(IVirtual_New(4), IVirtual_Delete);
            Assert::AreEqual(4, sptr->GetNumber());
        }

        TEST_METHOD(UniqueConstructor)
        {
            std::unique_ptr<IVirtual, decltype(IVirtual_Delete)> uptr(IVirtual_New(6), IVirtual_Delete);
            Assert::AreEqual(6, uptr->GetNumber());
        }

    };
}

但是当我添加 UniqueConstructor 方法停止测试项目的编译。

C2207: 'std::_Compressed_pair<_Ty1,_Ty2,false>::_Myval1': a member of a class template cannot acquire a function type

我假设这与析构函数有关,但我无法确定到底发生了什么。