C++在其他cpp文件中创建窗口(不在WinMain中)

我有一个函数,它位于与WinMain不同的cpp文件中,调用时将创建一个窗口。但是,该新窗口的windows类已在WinMain中声明并注册。现在,当我在单独的函数中创建窗口时,我被迫重新声明CreateWindowEx函数的第二个和第三个变量:

_In_opt_  LPCTSTR lpClassName,
_In_opt_  LPCTSTR lpWindowName,

因为实际执行创建的函数的位置无法访问在WinMain中创建的那些变量。现在我的疑问是,我的程序实际上使用的是我在WinMain中注册的窗口类吗?据我所知,重新定义这些变量并创建远离WinMain函数的函数可能会导致编译器采用其他一些标准窗口类。那么,我的程序实际上使用的是我在WinMain中注册的窗口类吗?

编辑:给出更多代码

//+++++++++++++++++++++++++++++++++++++带有win main的cpp文件:

INT WINAPI WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPSTR lpCmdLine, int nCmdShow)
{

...//previous code made the main window of the program and so forth

const char g_szClassName2[] = "windowClass2";//name of the window class
WNDCLASSEX winClass2;
HWND invisHWnd;

winClass2.cbSize         = sizeof(WNDCLASSEX);
winClass2.style          = 0;
winClass2.lpfnWndProc    = WndProcedure2;
winClass2.cbClsExtra     = 0;
winClass2.cbWndExtra     = 0;
winClass2.hInstance     = hInstance;
winClass2.hIcon         = LoadIcon(NULL, IDI_APPLICATION);
winClass2.hCursor       = LoadCursor(NULL, IDC_ARROW);
winClass2.hbrBackground = (HBRUSH)(COLOR_WINDOW+1);
winClass2.lpszMenuName  = NULL;
winClass2.lpszClassName = g_szClassName2;
winClass2.hIconSm       = LoadIcon(NULL, IDI_APPLICATION);

RegisterClassEx(&winClass2);

... //other code irrelevant to issue

}

//+++++++++++++++++++++++++++++++++++++其他cpp文件:

void otherCppFile::creatingWindow()
{

    const char g_szClassName2[] = "windowClass2";//name of the window class
    const char WndName2[] = "winClass2";//name of the window class

    HWND windowHandle = CreateWindowEx(0,
                      g_szClassName2,
                      WndName2,
                      WS_OVERLAPPEDWINDOW,
                      0,
                      0,
                      800,
                      500,
                      NULL,
                      NULL,
                      NULL,
                      NULL);
}

这最后一个函数是否使用在WinMain中注册的窗口类,即使它不位于WinMain中,并且在函数中重新声明了一些变量?