I have a require(“config.php”) with arrays, but still get Undefined variable error

尝试添加

 global $car_park;

见 manual page on variable scope 更多信息。

尽管保罗描述了发生的事情,我还是会再解释一遍。

When you create a variable it belongs to a particular scope. A scope is an area where a variable can be used.

例如,如果我要这样做

$some_var = 1;

function some_fun()
{
   echo $some_var;
}

$some_var = 1;

function some_fun()
{
   global $some_var; //Call the variable into the function scope!
   echo $some_var;
}

反之亦然,因此您不能执行以下操作

function init()
{
   $some_var = true;
}

init();

if($some_var) // this is not defined.
{

}

有几种方法可以解决这个问题,但最简单的方法是使用 $GLOBALS

所以

$GLOBALS['config'] = array(
   'Some Car' => 22
);

function do_something()
{
   echo $GLOBALS['config']['some Car']; //works
}

另外,为了安全起见,请确保您的服务器在ini中关闭了register globals。 http://www.php.net/manual/en/security.globals.php

您可以尝试将其代理到您的函数中,例如:

function foo($bar){

(代码)

$Car=$bar〔3〕;

(代码)

}

Then when you call it:

回声FO($bar);