child_进程。fork未在打包的electron应用程序内启动express server

在塞缪尔·阿塔德的大力帮助下( https://github.com/MarshallOfSound

正如他所说:

the default electron app will launch the first file path provided to it
so `electron path/to/thing` will work
in a packaged state, that launch logic is not present
it will always run the app you have packaged regardless of the CLI args passed to it
you need to handle the argument manually yourself
and launch that JS file if it's passed in as the 1st argument
The first argument to fork simply calls `process.execPath` with the first
argument being the path provided afaik
The issue is that when packaged Electron apps don't automatically run the
path provided to them
they run the app that is packaged within them

fork 实际上是 spawn process.execPath 并将fork的第一个参数作为第二个参数传递给spawn。

打包应用程序中发生的情况是 过程执行路径 不是electron,而是打包的应用程序本身。所以如果你试着 产卵 ,应用程序将一次又一次打开。

if (process.argv[1] === '--start-server') {
   require('./server/mainServer.js')
   return
}

require('./local/mainLocal.js')
require('child_process').spawn(process.execPath, ['--start-server'])

process.argv[1] 将为空,因此服务器无法启动。然后,它将执行electron部分(在我的例子中是mainLocal)并重新启动应用程序,但这次通过了 argv

非常感谢塞缪尔。