从PHP脚本返回JSON和HTML

不要 echo 行,保存在变量中。构造一个简单数组 $response = array( 'html' => $the_line_you_wanted_to_echo, 'jsobject' => $the_object_you_were_going_to_send_back ); 把它寄回去(通过 json_encode 相反。

另外,您不需要json2.js,jquery有一个优秀的json解析器。

你可以这样装 $.get( 'your/url', { params : here }, success, 'JSON' );

更改以匹配新引入的迭代。

for ($x = 0, $num_rows = mysql_num_rows($result); $x < $num_rows; $x++) {
    $row = mysql_fetch_assoc($result);
    $comments[$x] = array(
        "name" => stripslashes($row["name"]), 
        "comment" => stripslashes($row["comment"]), 
        "datetime" => date("m/d/Y g:i A", strtotime($comment['datetime']))
    );        
}

$html = "<h1 style='margin-left: 25px;'>$num_rows Comments for $mysql_table</h1>";

echo json_encode(array( 'comments' => $comments, 'html' => $html ));

然后,在您的javascript中,

function success( parsedObject ){
    parsedObject.html; // "<h1 style..."
    parsedObject.comments; // an array of objects
    parsedObject.comments[0].name 
    + " on " + parsedObject.comments[0].datetime 
    + " said \n" + parsedObject.comments[0].comment; // for example
}

如上所述,只需将您想要返回的所有数据放到一个数组中并对其进行编码。

<?php

echo json_encode(array(
    'html' => $html,
    'foo' => $bar,
    'bar' => $baz
));

?>

另外,如前所述,您不需要json2.js。通过将数据类型指定为JSON,可以使用jquery的任何ajax函数解析JSON数据。

$.ajax({
    type: 'POST',
    url: 'path/to/php/script.php',
    dataType: 'json',
    data: 'foo=bar&baz=whatever',
    success: function($data) {
        var html = $data.html;
        var foo = $data.foo;
        var bar = $data.bar;

        // Do whatever.
    }
});

编辑 几乎和霍丽亚说的一样。我能看到的另一个变化是,如果你想要相同数组中的所有内容。

例如:

菲律宾:

<?php

// You have your comment array sent up as you want as $comments
// Then just prepend the HTML string onto the beginning of your comments array.
// So now $comments[0] is your HTML string and everything past that is your comments.
$comments = array_unshift($comments, $your_html_string);

echo json_encode($comments);

?>

jQuery:

$.ajax({
    type: 'POST',
    url: 'path/to/php/script.php',
    dataType: 'json',
    data: 'foo=bar&baz=whatever',
    success: function($comments) {
        // Here's your html string.
        var html = $comments[0];

        // Make sure to start at 1 or you're going to get your HTML string twice.
        // You could also skip storing it above, start at 0, and add a bit to the for loop:
        // if x == 0 then print the HTML string else print comments.
        for (var x = 1; x < $comments.length; x++) {
            // Do what you want with your comments.
            // Accessed like so:
            var name = $comments[x].name;
            var comment = $comments[x].comment;
            var datetime = $comments[x].datetime;
        }
    }
});

你可能对 jLinq ,一个允许您查询javascript对象的javascript库。一个示例查询是:

var results = jLinq.from(data.users)
    .startsWith("first", "a")
    .orEndsWith("y")
    .orderBy("admin", "age")
    .select();

jlinq支持查询嵌套对象和执行联接。例如:

var results = jLinq.from(data.users) 
    .join(data.locations, //the source array 
        "location", //the alias to use (when joined) 
        "locationId", // the location id for the user 
        "id" // the id for the location 
    ) 
    .select(function(r) { 
        return { 
            fullname:r.first + " " + r.last, 
            city:r.location.city, 
            state:r.location.state 
        }; 
    });