如何在nhibernate中查询持久化对象的属性的子属性?

我觉得很傻。

public class Uber
{
   public Foo Foo { get; set; }
   public Bar Bar { get; set; }
}

public class Foo
{
   public string Name { get; set; }
}

...

var ubercharged = session.CreateCriteria(typeof(Uber))
.Add(Expression.Eq("Foo.Name", "somename"))
.UniqueResult<Uber>();
return ubercharged;

这将引发“无法解析属性”错误。

我做错什么了?我想查询一个具有属性foo的uber对象,该属性的名称为“somename”。

使用Fluent nhibernate更新了现实生活中的示例,存储库调用:

    public UserPersonalization GetUserPersonalization(string username)
    {
        ISession session = _sessionSource.GetSession();

        var personuser = session.CreateCriteria(typeof(UserPersonalization))
            .Add(Expression.Eq("User.Username", username))
            .UniqueResult<UserPersonalization>();
        return personuser;

    }

类/映射:

public class User
{
    public virtual Guid UserId { get; set; }
    public virtual string Username { get; set; }
    public virtual string Email { get; set; }
    public virtual string PasswordHash { get; set; }
    public virtual string PasswordSalt { get; set; }
    public virtual bool IsLockedOut { get; set; }
    public virtual bool IsApproved { get; set; }

}

public class Person
{
    public virtual int PersonId { get; set; }
    public virtual string Name { get; set; }
    public virtual Company Company { get; set; }

}

public class UserPersonalization
{
    public virtual int UserPersonalizationId { get; set; }
    public virtual Person Person { get; set; }
    public virtual User User { get; set; }
}

public class UserMap : ClassMap<User>
{
    public UserMap()
    {
        Id(x => x.UserId).GeneratedBy.Guid().ColumnName("UserId");
        Map(x => x.Username);
        Map(x => x.PasswordHash);
        Map(x => x.PasswordSalt);
        Map(x => x.Email);
        Map(x => x.IsApproved);
        Map(x => x.IsLockedOut);
    }
}

public class UserPersonalizationMap : ClassMap<UserPersonalization>
{
    public UserPersonalizationMap()
    {
        WithTable("UserPersonalization");
        Id(x => x.UserPersonalizationId).ColumnName("UserPersonalizationId");
        References(x => x.Person).ColumnName("PersonId");
        References(x => x.User).ColumnName("UserId");
    }
}

public class PersonMap : ClassMap<Person>
{
    public PersonMap()
    {
        Id(x => x.PersonId).ColumnName("PersonId");
        Map(x => x.Name);
        References(x => x.Company).ColumnName("CompanyId");
    }
}