比如说:

def deep_transform_values(hash)
  return hash unless hash.is_a?(Hash)

  hash.transform_values do |val|
    if val.is_a?(Array) && val.length == 1
      val.first
    else
      deep_transform_values(val)
    end
  end
end

测试内容如下:

hash = {
  'key1' => ['value'],
  'key2' => {
    'sub1' => ['string'],
    'sub2' => ['string'],
  },
  'shippingInfo' => {
                   'shippingType' => ['Calculated'],
                'shipToLocations' => ['Worldwide'],
              'expeditedShipping' => ['false'],
        'oneDayShippingAvailable' => ['false'],
                   'handlingTime' => ['3'],
                   'an_integer' => 1,
                   'an_empty_array' => [],
                   'an_array_with_more_than_one_elements' => [1,2],
                   'a_symbol' => :symbol,
                   'a_string' => 'string'
    }
  }

给予:

{
  "key1"=>"value",
  "key2"=>{
    "sub1"=>"string",
    "sub2"=>"string"
  },
  "shippingInfo"=> {
    "shippingType"=>"Calculated",
    "shipToLocations"=>"Worldwide",
    "expeditedShipping"=>"false",
    "oneDayShippingAvailable"=>"false",
    "handlingTime"=>"3",
    "an_integer"=>1,
    "an_empty_array"=>[],
    "an_array_with_more_than_one_elements"=>[1, 2],
    "a_symbol"=>:symbol,
    "a_string"=>"string"
  }
}

根据你在评论中提出的问题,我想逻辑会有所改变:

class Hash
  def deep_transform_values
    self.transform_values do |val|
      next(val.first) if val.is_a?(Array) && val.length == 1
      next(val) unless val.respond_to?(:deep_transform_values)

      val.deep_transform_values
    end
  end
end

另一种方法是,考虑使用对象并允许初始值设定项为您解构一些键。

很多像我这样的人开始使用ruby来支持perl的原因之一是对象的更好的表达方式取代了数组和散列等原语。好好利用它!

class ShippingStuff # You've kept the data vague

  def initialize key1:, key2:, shippingInfo:
    @blk = -> val {
      val.respond_to?(:push) && val.size == 1 ?
          val.first :
          cleankeys(val)
    }
    @key1 = cleankeys key1
    @key2 = cleankeys key2
    @shippingInfo = shippingInfo
  end

  attr_reader :key1, :key2, :shippingInfo

  # basically a cut down version of what
  # Sebastian Palma answered with
  def cleankeys data
    if data.respond_to? :transform_values
      data.transform_values &@blk
    else
      @blk.call(data)
    end
  end

end


hash = {
  'key1' => ['value'],
  'key2' => {
    'sub1' => ['string'],
    'sub2' => ['string'],
  },
  'shippingInfo' => {
                   'shippingType' => ['Calculated'],
                'shipToLocations' => ['Worldwide'],
              'expeditedShipping' => ['false'],
        'oneDayShippingAvailable' => ['false'],
                   'handlingTime' => ['3'],
  }
}

shipper = ShippingStuff.new hash.transform_keys!(&:to_sym)
shipper.key1
# "value"
shipper.key2
# {"sub1"=>"string", "sub2"=>"string"}
shipper.shippingInfo
# {"shippingType"=>["Calculated"], "shipToLocations"=>["Worldwide"], "expeditedShipping"=>["false"], "oneDayShippingAvailable"=>["false"], "handlingTime"=>["3"]}

同样的道理,我甚至会 Info 为 shippingInfo 数据。

如果 key1 和 key2 很有活力,但也有办法( double splat 其中之一)。

hash = {
  'key1' => ['value'],
  'key2' => {
    'sub1' => ['string'],
    'sub2' => ['string'],
  },
  'shippingInfo' => {
                   'shippingType' => ['Calculated'],
                'shipToLocations' => ['Worldwide', 'Web'],
              'expeditedShipping' => ['false'],
        'oneDayShippingAvailable' => ['false'],
                   'handlingTime' => ['3'],
    }
  }

def recurse(hash)
  hash.transform_values do |v|
    case v
    when Array
      v.size == 1 ? v.first : v
    when Hash
      recurse v
    else
      # raise exception
    end
  end
end

recurse hash
  #=> {"key1"=>"value",
  #    "key2"=>{
  #      "sub1"=>"string",
  #      "sub2"=>"string"
  #    },
  #    "shippingInfo"=>{
  #      "shippingType"=>"Calculated",
  #      "shipToLocations"=>["Worldwide", "Web"],
  #      "expeditedShipping"=>"false",
  #      "oneDayShippingAvailable"=>"false",
  #      "handlingTime"=>"3"
  #    }
  #  }