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在文本中用*替换指定短语

redaction gsub ruby

1

Blank Reaver · 技术社区 · 7 年前

我的目的是接受文本的一段,并找到我要编辑或替换的特定短语。

我创建了一个方法,该方法将参数作为文本字符串接受。我将该字符串分解为单个字符。将比较这些字符,如果它们匹配,我会将这些字符替换为 * 。

def search_redact(text)
  str = ""

  print "What is the word you would like to redact?"
  redacted_name = gets.chomp
  puts "Desired word to be REDACTED #{redacted_name}! "
  #splits name to be redacted, and the text argument into char arrays
  redact = redacted_name.split("")
  words = text.split("")

  #takes char arrays, two loops, compares each character, if they match it 
  #subs that character out for an asterisks
  redact.each do |x|
    if words.each do |y|
      x == y
      y.gsub!(x, '*') # sub redact char with astericks if matches words text
       end # end loop for words y
    end # end if statment
 end # end loop for redact x

# this adds char array to a string so more readable  
words.each do |z|
  str += z
end
# prints it out so we can see, and returns it to method
  print str
  return str
end

# calling method with test case
search_redact("thisisapassword")

#current issues stands, needs to erase only if those STRING of characters are 
# together and not just anywehre in the document

如果我输入了一个与文本其他部分共享字符的短语,例如,如果我调用:

search_redact("thisisapassword")

然后它也将替换该文本。当它接受用户的输入时,我只想去掉文本密码。但它看起来是这样的:

thi*i**********

请帮忙。

1 回复 | 直到 7 年前

1

Anthony 7 年前

这是一个用于在字符串中查找子字符串的经典窗口问题。有很多方法可以解决这个问题,其中一些方法比其他方法效率更高,但我将为您提供一个简单的方法,尽可能多地使用您的原始代码:

def search_redact(text)
  str = ""

  print "What is the word you would like to redact?"
  redacted_name = gets.chomp
  puts "Desired word to be REDACTED #{redacted_name}! "
  redacted_name = "password"
  #splits name to be redacted, and the text argument into char arrays
  redact = redacted_name.split("")
  words = text.split("")

  words.each.with_index do |letter, i|
    # use windowing to look for exact matches
    if words[i..redact.length + i] == redact
      words[i..redact.length + i].each.with_index do |_, j|
        # change the letter to an astrisk
        words[i + j] = "*"
      end
    end
  end

  words.join
end

# calling method with test case
search_redact("thisisapassword")

我们的想法是利用阵列 == 这让我们可以说 ["a", "b", "c"] == ["a", "b", "c"] .现在我们只需遍历输入,然后问这个子数组是否等于另一个子数组。如果它们确实匹配,我们知道需要更改值,因此我们循环遍历每个元素,并将其替换为 * 。