在neo4j中使用cypher收集不同路径长度的节点

我试图收集不同路径长度的节点,并根据路径长度分配一个变量。不在路径中的节点=分离,路径长度1=半,路径长度>1=阶梯。

我有下面的密码,但当返回收集的名单没有什么是返回,即使每个部分的工作在其上的罚款。

match (a:Test) where not (a)-[]-() with a, COLLECT(DISTINCT a) as detached  
match (a:Test)-[r]-() with a,detached,count(r) as rels where rels = 1 
match path = (a)-[]->() with detached, COLLECT(DISTINCT NODES(path)) AS semis 
match path = (a)-[:NEIGHBOURING_BUILDING*]-() where length(path) > 1 with detached, semis, COLLECT(DISTINCT NODES(path)) AS terraces 
return detached, semis, terraces

我现在正在使用这个测试网络

create (:Test{id:1}) 
create (:Test{id:2})
create (:Test{id:3})-[:NEIGHBOUR]->(:Test{id:4}) 
create (:Test{id:5})-[:NEIGHBOUR]->(:Test{id:6})<-[:NEIGHBOUR]-(:Test{id:7})
create (:Test{id:8})-[:NEIGHBOUR]->(:Test{id:9})
create (:Test{id:10})-[:NEIGHBOUR]->(:Test{id:11})<-[:NEIGHBOUR]-(:Test{id:12})

如何将每种路径类型中的节点收集到一个列表中?