我正在工作的站点有一个数据库表,其中充满了词汇表术语。我正在构建一个函数,它将使用一些HTML并用工具提示链接替换词汇表术语的第一个实例。
我想底线是,我需要忽略文本,如果它:
这是我目前掌握的情况。我希望有人能想出一个聪明的解决办法。
function insertGlossaryLinks($html)
{
// Get glossary terms from database, once per request
static $terms;
if (is_null($terms)) {
$query = Doctrine_Query::create()
->select('gt.title, gt.alternate_spellings, gt.description')
->from('GlossaryTerm gt');
$glossaryTerms = $query->rows();
// Create whole list in $terms, including alternate spellings
$terms = array();
foreach ($glossaryTerms as $glossaryTerm) {
// Initialize with title
$term = array(
'wordsHtml' => array(
h(trim($glossaryTerm['title']))
),
'descriptionHtml' => h($glossaryTerm['description'])
);
// Add alternate spellings
foreach (explode(',', $glossaryTerm['alternate_spellings']) as $alternateSpelling) {
$alternateSpelling = h(trim($alternateSpelling));
if (empty($alternateSpelling)) {
continue;
}
$term['wordsHtml'][] = $alternateSpelling;
}
$terms[] = $term;
}
}
// Do replacements on this HTML
$newHtml = $html;
foreach ($terms as $term) {
$callback = create_function('$m', 'return \'<a href="javascript:void(0);" class="glossary-term" title="'.$term['descriptionHtml'].'"><span>\'.$m[0].\'</span></a>\';');
$term['wordsHtmlPreg'] = array_map('preg_quote', $term['wordsHtml']);
$pattern = '/\b('.implode('|', $term['wordsHtmlPreg']).')\b/i';
$newHtml = preg_replace_callback($pattern, $callback, $newHtml, 1);
}
return $newHtml;
}