这个递归的windows cmd脚本有什么问题?阿克曼做得不好

我在试着计算阿克曼函数。我要达到的目标是 http://rosettacode.org/wiki/Ackermann_function .

使用测试脚本,测试04给出了正确的5。然而,测试14给出5而不是6,测试24给出5而不是11。

我哪里做错了?

::echo off
set depth=0
:ack
if %1==0 goto m0
if %2==0 goto n0

:else
set /a n=%2-1
set /a depth+=1
call :ack %1 %n%
set t=%errorlevel%
set /a depth-=1
set /a m=%1-1
set /a depth+=1
call :ack %m% %t%
set t=%errorlevel%
set /a depth-=1
if %depth%==0 ( exit %t% ) else ( exit /b %t% )

:m0
set/a n=%2+1
if %depth%==0 ( exit %n% ) else ( exit /b %n% )

:n0
set /a m=%1-1
set /a depth+=1
call :ack %m% %2
set t=%errorlevel%
set /a depth-=1
if %depth%==0 ( exit %t% ) else ( exit /b %t% )

我用这个脚本来测试

@echo off
cmd/c ackermann.cmd %1 %2
echo Ackermann of %1 %2 is %errorlevel%

测试11的样本输出给出:

>test 1 1
>set depth=0
>if 1 == 0 goto m0
>if 1 == 0 goto n0
>set /a n=1-1
>set /a depth+=1
>call :ack 1 0
>if 1 == 0 goto m0
>if 0 == 0 goto n0
>set /a m=1-1
>set /a depth+=1
>call :ack 0 0
>if 0 == 0 goto m0
>set/a n=0+1
>if 2 == 0 (exit 1  )  else (exit /b 1  )
>set t=1
>set /a depth-=1
>if 1 == 0 (exit 1  )  else (exit /b 1  )
>set t=1
>set /a depth-=1
>set /a m=1-1
>set /a depth+=1
>call :ack 0 1
>if 0 == 0 goto m0
>set/a n=1+1
>if 1 == 0 (exit 2  )  else (exit /b 2  )
>set t=2
>set /a depth-=1
>if 0 == 0 (exit 2  )  else (exit /b 2  )
Ackermann of 1 1 is 2