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ASP.NETCore2.1:如何将Gulp与npm一起用于项目依赖项

asp.net-core-2.0 gulp asp.net-core npm

LatentDenis · 技术社区 · 8 年前

Bower 如果ASP.NETCore2.0已经过时,我需要找到一种同样有效的方法来缩小/注入npm中的依赖项。

gulp ,并使用 npm ,我正在将所有依赖项更新到 node_modules package.json 要注入到 wwwroot

我正在学习Shawn Wildermuth的教程: https://wildermuth.com/2017/11/19/ASP-NET-Core-2-0-and-the-End-of-Bower 还有他的“ “需要在中列出依赖项目录。” Gulp 文件:

// Dependency Dirs
var deps = {
    "jquery": {
        "dist/*": ""
    },
    "bootstrap": {
        "dist/**/*": ""
    },
};

gulp.task("scripts", function () {
    var streams = [];

    for (var prop in deps) {
        console.log("Prepping Scripts for: " + prop);
        for (var itemProp in deps[prop]) {
            streams.push(gulp.src("node_modules/" + prop + "/" + itemProp)
                .pipe(gulp.dest("wwwroot/vendor/" + prop + "/" + deps[prop][itemProp])));
        }
    }

    return merge(streams);
});

是否可以在不列出列表中所有依赖项目录的情况下执行此操作 吞咽 而是扫描文件以从中携带特定文件 节点单元 网站根目录

package.json :

{
    "version": "1.0.0",
    "name": "asp.net",
    "dependencies": {
        "jquery": "3.3.1",
        "bootstrap": "4.1.1"
    },
    "devDependencies": {
        "gulp": "3.9.1",
        "gulp-concat": "2.6.1",
        "gulp-cssmin": "0.1.7",
        "gulp-uglify": "2.0.1",
        "rimraf": "2.6.1"
    }
}

这是我余下的时间 gulpfile.js :

/// <binding BeforeBuild='clean, min, scripts' Clean='clean' />
"use strict";

var gulp = require("gulp"),
    rimraf = require("rimraf"),
    concat = require("gulp-concat"),
    cssmin = require("gulp-cssmin"),
    uglify = require("gulp-uglify");

var paths = {
    webroot: "./wwwroot/"
};

paths.js = paths.webroot + "js/**/*.js";
paths.minJs = paths.webroot + "js/**/*.min.js";
paths.css = paths.webroot + "css/**/*.css";
paths.minCss = paths.webroot + "css/**/*.min.css";
paths.concatJsDest = paths.webroot + "js/site.min.js";
paths.concatCssDest = paths.webroot + "css/site.min.css";

gulp.task("clean:js", function (cb) {
    rimraf(paths.concatJsDest, cb);
});

gulp.task("clean:css", function (cb) {
    rimraf(paths.concatCssDest, cb);
});

gulp.task("clean", ["clean:js", "clean:css"]);

gulp.task("min:js", function () {
    return gulp.src([paths.js, "!" + paths.minJs], { base: "." })
        .pipe(concat(paths.concatJsDest))
        .pipe(uglify())
        .pipe(gulp.dest("."));
});

gulp.task("min:css", function () {
    return gulp.src([paths.css, "!" + paths.minCss])
        .pipe(concat(paths.concatCssDest))
        .pipe(cssmin())
        .pipe(gulp.dest("."));
});

gulp.task("min", ["min:js", "min:css"]);

我已经看到了一些解决方案,它们简单地从

有什么帮助吗?