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web窗体中的DotNetOpenAuth和ReturnToUrl

dotnetopenauth asp.net

1

Å¡ljaker · 技术社区 · 16 年前

我在用 asp.net 静态化 .

页面加载

OpenIdLogin1.ReturnToUrl = @"~/Login"

当我登录并返回到调用页时,会收到以下错误消息:

http://localhost:12345/Login?dnoa.receiver=ctl00_phContent_ctl00_OpenIdLogin1&dnoa.UsePersistentCookie=Session&dnoa.userSuppliedIdentifier=https://www.google.com/accounts/o8/id )与实际URL不匹配( http://localhost:12345/Templates/Pages/Login/Login.aspx?dnoa.receiver=ctl00_phContent_ctl00_OpenIdLogin1&dnoa.UsePersistentCookie=Session&dnoa.userSuppliedIdentifier=https://www.google.com/accounts/o8/id&openid.ns=http://specs.openid.net/auth/2.0

如何将实际url更改为虚拟url?

任何帮助都将不胜感激。

2 回复 | 直到 16 年前

1

3

Andrew Arnott 16 年前

在你的电话里 GetResponse ,传入 HttpRequestInfo 对象,用希望DotNetOpenAuth将其视为传入URL的URL进行初始化。

2

Å¡ljaker 16 年前

我解决了这个问题:

var openId = new OpenIdRelyingParty();
HttpContext httpContext = HttpContext.Current;

var headers = new WebHeaderCollection();
foreach (string header in httpContext.Request.Headers)
{
    headers.Add(header, httpContext.Request.Headers[header]);
}

string requestUrl = string.Format("http://localhost:12345/Login/{0}",
                                   httpContext.Request.Url.Query);

var requestInfo = new HttpRequestInfo(httpContext.Request.HttpMethod,
                                        new Uri(requestUrl),
                                        httpContext.Request.RawUrl, headers,
                                        httpContext.Request.InputStream);

var response = openId.GetResponse(requestInfo);