代码之家 › 专栏 › 技术社区 › Jeff Tian

如何在mongo数据库中进行联合表查询?

aggregation-framework mongodb

1

Jeff Tian · 技术社区 · 8 年前

现在我有两个mongo系列:

+--------------+--------------+
|    id        |     name     |
+--------------+--------------+
|     1        |   good name  |
+--------------+--------------+
|     2        |   bad name   |
+--------------+--------------+

位置

+--------------+---------------+-------------------+
|      id      |    companyId  |      name         |
+--------------+---------------+-------------------+
|      1       |      1        |     bad position  |
+--------------+---------------+-------------------+
|      2       |      2        |    good position  |
+--------------+---------------+-------------------+

现在我需要允许通过模糊匹配名称来搜索职位,无论是公司还是职位名称。例如,如果我按名称“good”搜索,结果应该是2个位置。因为对于职位1,它的公司名称包含“good”,而对于职位2,它自己的名称包含“good”。

那我该怎么安排呢 aggregation pipelines 为了达到这个目的?

我尝试了以下方法,但无效:

const lookup = {
  from: "companies",
  localField: "companyId",
  foreignField: "_id",
  as: "companies"
};

const match = {
  $or: [
    {
      name: { $regex: companyOrPositionName }
    },
    {
      "companies": { name: { $regex: companyOrPositionName } }
    }
  ]
};

return await position.aggregate([{ $lookup: lookup }, { $match: match }]);

有人能帮忙吗?提前谢谢!

1 回复 | 直到 8 年前

1

Ashh 8 年前

你可以在下面试试

position.aggregate([
  { "$lookup": {
    "from": "companies",
    "let": { "companyId": "$_id" },
    "pipeline": [
      { "$match": { "$expr": { "$eq": [ "$_id", "$$companyId" ] } } },
      { "$project": { "name": 1 }}
    ],
    "as": "companyName"
  }},
  { "$unwind": "$companyName" },
  { "$match": {
    "$or": [
      { "name": { "$regex": "good" }},
      { "companyName.name": { "$regex": "good" }}
    ]
  }}
])

find 查询

const companies = await Companies.find({ "name": { "$regex": "good" }})
const ids = companies.map(company => company._id)

position.find({
  "$or": [
    { "companyId": { "$in": ids }},
    { "name": { "$regex": "good" }}
  ]
})