根据命令链中的条件在中间命令中退出

the Docker's run command documentation:

docker run [OPTIONS] IMAGE [COMMAND] [ARG...]

您可以通过调用内联shell脚本来运行一系列命令。

bash 作为 [COMMAND] ,和 -c 'inline script' 作为 [ARG...]

例子:

docker run --health-cmd image_foo bash -c 'cmd_1; cmd_2; ...; cmd_j; cmd_k; :'

: exit 0 ).

作为一个简单的逻辑问题,运行一系列命令并退出 退出0

#!/usr/bin/env bash

# With if, then
if ! { true && true && true && true; }; then
  exit 0 # will not exit
fi

if ! { true && true &&  && false; }; then
  exit 0 # will exit
fi

if ! true || ! true || ! true || ! true; then
  exit 0 # will not exit
fi

if ! true || ! false || ! true || ! true; then
  exit 0 # will exit
fi

# With logic operators only
! { true && true && true && true; } && exit 0 # will not exit

! { false && true && true && true; } && exit 0 # will exit

{ ! true || ! true || ! true || ! true; } && exit 0 # will not exit

{ ! true || ! true || ! false || ! true; } && exit 0 # will exit

true 和 false

带有错误陷阱的其他解决方案:

#!/usr/bin/env bash

trap 'exit 0' ERR # exit 0 on an error

true # successful command
true # successful command
true # successful command
false # will trigger the ERR trap and exit 0
true # successful command
true # successful command

实施示例:

#!/usr/bin/env bash

i=0
! {
    { echo $((++i)); true; } &&
    { echo $((++i)); true; } &&
    { echo $((++i)); false; } && # Will stop here at i=3
    { echo $((++i)); true; } &&
    { echo $((++i)); true; }
  } && exit 0

输出:

1
2
3

(cmd_k || exit 0) && true

exit true . 如果你不在乎 cmd_k 不管成功与否,你只要

cmd_k; true