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在可序列化C类上使用不带xmlaray的xmlarayitem属性

xml-deserialization serializable xml-serialization xml c#

Sarah Vessels · 技术社区 · 14 年前

我希望XML采用以下格式:

<configuration><!-- Only one configuration node -->
  <logging>...</logging><!-- Only one logging node -->
  <credentials>...</credentials><!-- One or more credentials nodes -->
  <credentials>...</credentials>
</configuration>

我正在创建一个类 Configuration 那有 [Serializable] 属性。要序列化凭据节点,我有以下功能:

[XmlArray("configuration")]
[XmlArrayItem("credentials", typeof(CredentialsSection))]
public List<CredentialsSection> Credentials { get; set; }

但是,当我将其序列化为XML时,XML的格式如下:

<configuration>
  <logging>...</logging>
  <configuration><!-- Don't want credentials nodes nested in a second
                      configuration node -->
    <credentials>...</credentials>
    <credentials>...</credentials>
  </configuration>
</configuration>

如果我删除 [XmlArray("configuration")] 行,我得到以下信息:

<configuration>
  <logging>...</logging>
  <Credentials><!-- Don't want credentials nodes nested in Credentials node -->
    <credentials>...</credentials>
    <credentials>...</credentials>
  </Credentials>
</configuration>

我如何用我想要的方式序列化这个,用多个 <credentials> 单个根节点内的节点 <configuration> ?我想在不需要执行的情况下完成这个任务 IXmlSerializable 并进行自定义序列化。我的课是这样描述的:

[Serializable]
[XmlRoot("configuration")]
public class Configuration : IEquatable<Configuration>

1 回复 | 直到 14 年前

Mikael Svenson 14 年前

以下内容应按您希望的方式正确序列化。线索正在 [XmlElement("credentials")] 名单上。我是通过使用您的XML,在Visual Studio中从中生成一个模式(XSD)来实现这一点的。然后在架构上运行xsd.exe以生成类。(和一些小的编辑)

public class CredentialsSection
{
    public string Username { get; set; }
    public string Password { get; set; }
}

[XmlRoot(Namespace = "", IsNullable = false)]
public class configuration
{
    /// <remarks/>
    public string logging { get; set; }

    /// <remarks/>
    [XmlElement("credentials")]
    public List<CredentialsSection> credentials { get; set; }

    public string Serialize()
    {
        var credentialsSection = new CredentialsSection {Username = "a", Password = "b"};
        this.credentials = new List<CredentialsSection> {credentialsSection, credentialsSection};
        this.logging = "log this";
        XmlSerializer s = new XmlSerializer(this.GetType());
        StringBuilder sb = new StringBuilder();
        TextWriter w = new StringWriter(sb);
        s.Serialize(w, this);
        w.Flush();
        return sb.ToString();
    }
}

给出以下输出

<?xml version="1.0" encoding="utf-16"?>
<configuration xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <logging>log this</logging>
  <credentials>
    <Username>a</Username>
    <Password>b</Password>
  </credentials>
  <credentials>
    <Username>a</Username>
    <Password>b</Password>
  </credentials>
</configuration>