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在ruby中,直接传递方法名或通过用户输入响应方法有什么区别?

ruby

0

Ishan Patel · 技术社区 · 7 年前

我编写了以下代码:

obj = Object.new

def obj.talk
    puts "Talk called"
end

if obj.respond_to?(talk)
    obj.send(talk)
else
    puts "No talk"
end

输出如下:

undefined local variable or method `talk' for main:Object (NameError)

但当我通过用户输入传递它时,它的作用是:

obj = Object.new

def obj.talk
    puts "Talk called"
end

request = gets.chomp

if obj.respond_to?(request)
    obj.send(request)
else
    puts "No talk"
end

哪些输出 Talk called 输入字符串时 talk

1 回复 | 直到 7 年前

1

0

Ishan Patel 7 年前

感谢@Amadan,它通过使用方法的符号名来工作。后续工作。

obj = Object.new;

def obj.talk
    puts "Talk called"
end

if obj.respond_to?(:talk)
    obj.send(:talk)
else
    puts "No talk"
end

通话