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如何将控制器中的RequestBody定义为list,我得到了500个错误

spring-boot java

selvi · 技术社区 · 4 年前

我想通过搜索输入列表,参考下面的代码和有效载荷,我尝试,我得到解析器错误。

public class SearchInput {
    private List<SearchCriteria> criterias;

}

//搜索条件中的代码

public class SearchCriteria {
    private String key;
    private String operation;
    private String value;
}

//控制器代码

@PostMapping("/searchhh")
    public List<Profile> findProfiles(@RequestBody SearchInput input) {
        List<SearchCriteria> criterias = input.getCriterias();
                System.out.println("criterias=" + criterias);
        
        return null;
    }

//我累了

URL:
http://localhost:5555/matrimony/api/v1/profiles/searchhh

Request body:
[
  {
    "key": "g",
    "operation": "eq",
    "value": "m"
  },
  {
    "key": "name",
    "operation": "like",
    "value": "Rani"
  },
  {
    "key": "sh",
    "operation": "eq",
    "value": "Never"
  }
]

Response:
{
    "message": "JSON parse error: Cannot deserialize instance of `com.model.SearchInput` out of START_ARRAY token; nested exception is com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of `com.model.SearchInput` out of START_ARRAY token\n at [Source: (PushbackInputStream); line: 1, column: 1]",
    "status": 500,
    "timestamp": "2021-01-21T11:31:48.228796"
}

2 回复 | 直到 4 年前

Donato Amasa 4 年前

{
    "criterias" : [
        {
            "key": "g",
            "operation": "eq",
            "value": "m"
        },
        {
            "key": "name",
            "operation": "like",
            "value": "Rani"
        },
        {
            "key": "sh",
            "operation": "eq",
            "value": "Never"
        }
    ]
}

Ryuzaki L 4 年前

SearchCriteria 对象,因此您可以将该json直接解析为 List<SearchCriteria> 而且不需要 SearchInput 班

@PostMapping("/searchhh")
public List<Profile> findProfiles(@RequestBody List<SearchCriteria> input) {
            System.out.println("criterias=" + input);
    
    return null;
}