当按名称空间进行版本控制时,将xml序列化为适当对象的最佳方法是什么?

我有一个由名称空间控制的xml。我想将接收到的xml序列化为适当的对象,但我知道的唯一方法是必须对xml进行两次处理。首先发现名称空间,然后根据发现的名称空间序列化为适当类型的对象。对我来说,这似乎是非常低效的,必须有某种方法使用泛型或其他东西来获取适当类型的对象,而不需要“if namespace==x然后序列化到该”检查。

下面是我知道的实现这一点的唯一方法的示例。有更好或更有效的方法吗?

谢谢

using System;
using System.Text;
using System.Collections.Generic;
using System.Linq;
using Microsoft.VisualStudio.TestTools.UnitTesting;
using System.Xml.Linq;
using System.Xml;
using System.Xml.Serialization;
using System.IO;

namespace TestProject1
{
    [TestClass]
    public class UnitTest1
    {
        [TestMethod]
        public void TestMethod3()
        {
            //Build up an employee object to xml
            Schema.v2.Employee employee = new Schema.v2.Employee { FirstName = "First", LastName = "Last" };
            string xml = employee.ObjectToXml<Schema.v2.Employee>();

            //Now pretend I don't know what type I am receiving.
            string nameSpace = GetNamespace(xml);
            Object newemp;
            if (nameSpace == "Employee.v2")
                newemp = XmlSerializationExtension.XmlToObject<Schema.v2.Employee>(null, xml);
            else
                newemp = XmlSerializationExtension.XmlToObject<Schema.v1.Employee>(null, xml);

            // Check to make sure that the type I got was what I made.
            Assert.AreEqual(typeof(Schema.v2.Employee), newemp.GetType());
        }

        public string GetNamespace(string s)
        {
            XDocument z = XDocument.Parse(s);
            var result = z.Root.Attributes().
                    Where(a => a.IsNamespaceDeclaration).
                    GroupBy(a => a.Name.Namespace == XNamespace.None ? String.Empty : a.Name.LocalName,
                            a => XNamespace.Get(a.Value)).
                    ToDictionary(g => g.Key,
                                 g => g.First());

            foreach (System.Xml.Linq.XNamespace item in result.Values)
                if (item.NamespaceName.Contains("Employee")) return item.NamespaceName;

            return String.Empty;
        }
    }

    public static class XmlSerializationExtension
    {
        public static string ObjectToXml<T>(this T Object)
        {
            XmlSerializer s = new XmlSerializer(Object.GetType());
            using (StringWriter writer = new StringWriter())
            {
                s.Serialize(writer, Object);
                return writer.ToString();
            }
        }
        public static T XmlToObject<T>(this T Object, string xml)
        {
            XmlSerializer s = new XmlSerializer(typeof(T));
            using (StringReader reader = new StringReader(xml))
            {
                object obj = s.Deserialize(reader);
                return (T)obj;
            }
        }
    } 
}

namespace Schema.v1
{
    [XmlRoot(ElementName = "Employee", Namespace= "Employee.v1", IsNullable = false)]
    public class Employee
    {
        [XmlElement(ElementName = "FirstName")]
        public string FirstName { get; set; }
        [XmlElement(ElementName = "LastName")]
        public string LastName { get; set; }
    }
}
namespace Schema.v2
{
    [XmlRoot(ElementName = "Employee", Namespace = "Employee.v2", IsNullable = false)]
    public class Employee
    {
        [XmlAttribute(AttributeName = "FirstName")]
        public string FirstName { get; set; }
        [XmlAttribute(AttributeName = "LastName")]
        public string LastName { get; set; }
    }
}