作为函数调用参数的枚举模式匹配

enum CarType : Equatable {
    case wheeled(wheels: Int)
    case flying

    public static func ==(lhs: CarType, rhs: CarType) -> Bool {
        return lhs.enumName == rhs.enumName
    }

    var enumName: String {
        let stuff = "\(self)".split(separator: "(").first!
        return String(describing: stuff)
    }

}


var typesPresentAtMyParty = [CarType.wheeled(wheels:4), .wheeled(wheels:4), .flying]

let aKnownType = CarType.flying

if case aKnownType = typesPresentAtMyParty[2] {
    print("Was the type")
}

func isPresent(type: CarType, inArray: [CarType]) -> Bool {

    return inArray.filter {
        if case type = $0 {
            return true
        }
        return false
    }.first != nil

}

func isWheeled(inArray: [CarType]) -> Bool {

    return inArray.filter {
        if case .wheeled = $0 {
            return true
        }
        return false
        }.first != nil

}


isPresent(type: .flying, inArray: typesPresentAtMyParty)
isPresent(type: .wheeled, inArray: typesPresentAtMyParty) 

这里的最后一行没有编译。当我能做的时候 if case .wheeled = $0 忽略关联类型作为检查,我找不到在函数调用中执行相同操作的方法 isPresent(type: CarType, inArray: [CarType]) ,发送时 isPresent(type: .wheeled, inArray: typesPresentAtMyParty)

有没有一种方法可以编写一个只将枚举中有效的模式匹配部分作为参数的函数?