在c中拆分字典中的“路径变量”字符串#

假设提供的字符串包含第一个值作为关键字,第二个值是提供的字符串中的值

value1/672/value2/32/value3/21413

以下是实现上述目标的方法:

using System;
using System.Collections.Generic;
using System.Linq;

class Program
{
    static void Main()
    {
        string input = "value1/672/value2/32/value3/21413";
        string[] parts = input.Split('/');
        var dictionary = parts
            .Select((value, index) => new { value, index })
            .Where(x => x.index % 2 == 0) // Select only even indexed elements as keys
            .ToDictionary(x => x.value, x => parts[x.index + 1]); // Use the next element as value      
        
        foreach (var kvp in dictionary)   // Loop for printing the result only
        {
            Console.WriteLine($"{kvp.Key}: {kvp.Value}");   // Output the dictionary key and values
        }
    }
}

参考正在工作的.netfiddle here

如果你真的想这样做,你可以用几个LINQ操作符来完成,但我看不出有太多附加值:

var str = "value1/672/value2/32/value3/21413";

// Array containing [value1, 672, value2, 32, value3, 21413
var arr = str.Split('/');

arr
    // Zip gives you pairs between 2 collections, here i'm zipping arr with itself with first element skipped
    // this gives both the key => value but also the value=> key pairs
    // so this results in {value1, 672} which we want, but also in {672, value2} which we do not want
    .Zip(arr.Skip(1))
    // Keep only the even indexes to get rid of the pairs we don't want mentioned above
    .Where((item,index)=>index%2 == 0)
    // Convert those tuples to a dictionnary
    .ToDictionary(item=>item.First,item=>item.Second);