我的目的是返回基于所选年份的日期值,以及基于包含所有年份的完整数据集的数据集的最小日期值。查询始终返回2017年的最小日期值。我希望它返回整个数据集的最小start\u日期。
我得到的是min\u date\u over\u all\u years
orgA 2017-10-09
orgB 2017-10-08
min\u date\u over\u all\u years的要求结果为
orgA 2015-10-10
orgB 2014-10-09
请参见随附的小提琴示例:
http://sqlfiddle.com/#!9/c0f74/9
架构为:
CREATE TABLE IF NOT EXISTS `project` (
`project_id` int(11) NOT NULL AUTO_INCREMENT,
`p_name` varchar(10) NOT NULL,
`start_date` DATE NOT NULL,
`organisation_id` int(11) NOT NULL,
PRIMARY KEY (`project_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=6 ;
INSERT INTO `project` (`project_id`, `p_name`,
`start_date`, `organisation_id`)
VALUES
(1, 'testP1', '2017-10-09', 1),
(2, 'testP2', '2016-10-10', 1),
(3, 'testP3', '2015-10-10', 1),
(4, 'testP4', '2017-10-10', 2),
(5, 'testP5', '2014-10-10', 2),
(6, 'testP6', '2017-10-10', 1),
(7, 'testP7', '2016-10-10', 1),
(8, 'testP8', '2015-10-10', 1),
(9, 'testP9', '2017-10-08', 2),
(10, 'testP10', '2014-10-09', 2);
CREATE TABLE IF NOT EXISTS `organisation` (`organisation_id` int(11) NOT NULL AUTO_INCREMENT,
`org_name` varchar(10) NOT NULL,
PRIMARY KEY (`organisation_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=6 ;
INSERT INTO `organisation` (`organisation_id`, `org_name`
)
VALUES
(1, 'orgA'),
(2, 'orgB');
我尝试过的查询(以及更简单的子查询和Case版本)是:
SELECT o.org_name, MIN(p.start_date) AS min_date_2017, YEAR(p.start_date) AS year_selected,
(SELECT MIN(p.start_date) FROM project p2
INNER JOIN organisation o2 ON o2.organisation_id = p2.organisation_id
WHERE p2.organisation_id = o.organisation_id
GROUP BY o2.organisation_id) AS min_date_over_all_years
FROM organisation o
INNER JOIN project p on p.organisation_id = o.organisation_id
WHERE YEAR(p.start_date)=2017
GROUP BY o.organisation_id