我正在尝试创建一个简单的天气页面。我想从weather Underground API检索用户位置的坐标,然后检索位置的天气信息。我可以看到我坐标的JSON响应。然而,我在使用AJAX函数解析JSON并在HTML上显示它时遇到了问题。下面是我的代码
HTML:
<div class="container-fluid text-center">
<body>
<div id="forecast">
<h1>Weather at <span id="location"> </span></h1>
<div id="imgdiv">
<img id="img" src=""/>
</div>
<p>It is currently <span id="temp"> </span>°C with <span id="desc"> </span></p>
<p>Wind: <span id="wind"></span></p>
</body>
</div>
JQuery;
var Geo={};
var temp_f
//var key = â4d6eb96f1aa092b2â;
if (navigator.geolocation) {
navigator.geolocation.getCurrentPosition(success,error);
}
else {
alert('Geolocation is not supported');
}
function error() {
alert("That's weird! We couldn't find you!");
}
function success(position) {
Geo.lat = position.coords.latitude;
Geo.lng = position.coords.longitude;
Geo.url = "http://api.wunderground.com/api/4d6eb96f1aa092b2/forecast/geolookup/conditions/q/" + Geo.lat + "," + Geo.lng + ".json";
$.ajax({
url : Geo.url,
dataType : "json",
success : function(url) {
location = url['location']['city'];
temp_f = url['current_observation']['temp_f'];
$("#temp").html(temp_f);
}
});
}
我得到的位置和temp_f值为
undefined
我提到了一个非常相似的帖子
Weather Underground API with Ajax
但却不知道问题是什么?我是新的,所以请原谅,如果我错过了一些基本的东西。
