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在swift中使用多部分/表单数据上传带参数的图像

multipartform-data swift ios php

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Awais Fayyaz · 技术社区 · 7 年前

我正在尝试将图像上载到 具体的 我的服务器的路径。该路径将由发送自的参数确定 multipart/form-data 要求

问题 :图像未上载到指定路径,而是上载到我的服务器的根目录。

我正在调用一个具有php函数的API,以将该图像保存到指定路径。我认为PHP函数没有正确地从参数中获取路径。

我调用的API类似于

https://storage.myWebsiteName.com/upload_image.php/

upload\u图像的内容。php

   <?php
header('Access-Control-Allow-Origin: *'); 

//Unable to get path parameter and store in @target_dir, instead this function stores image in root
$target_dir = $_GET["path"];


$name = basename($_FILES["fileToUpload"]["name"]);
$target_file = $target_dir . $name;
$imageFileType = strtolower(pathinfo($target_file,PATHINFO_EXTENSION));
// Check if image file is a actual image or fake image

$actual_name = strtolower(
    pathinfo(
            $_FILES["fileToUpload"]["name"],PATHINFO_FILENAME));


    if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
        echo $name;
    } else {
        echo "Sorry, there was an error uploading your file.";
    }

?>

我从中获取图像 UIImagePickerController 并将图像传递给此函数 多部分/表单数据 要求

func postImageToDB(image : UIImage) {

    let imagePostUrlStr =  "https://myWebsiteName.com/upload_image.php/"

    guard let imageData = UIImagePNGRepresentation(image) else {
      return
    }
    //want to save my image to this directory which is inside root
    let params = ["path" : "Brainplow/001243192018125835"]

    Alamofire.upload(multipartFormData: { (multiPartFormData: MultipartFormData) in
      //append path parameter
      for (key, value) in params {
        multiPartFormData.append(value.data(using: String.Encoding.utf8)!, withName: key)
      }
      multiPartFormData.append(imageData, withName: "fileToUpload", fileName: "testfilename.png", mimeType: "image/png")

    }, to: imagePostUrlStr) { (result: SessionManager.MultipartFormDataEncodingResult) in
      switch result {
      case .success(request: let uploadRequest, _, _ ):


        uploadRequest.uploadProgress(closure: { (progress) in

          print("Upload Progress: \(progress.fractionCompleted)")

        })

        uploadRequest.responseString { response in
          print("printing response string")
          print(response.value as Any)
          print(response)
          print(response.result)

        }

      case .failure(let error):
        print(error.localizedDescription)
      }
    }


  }

笔记 :在php函数中,如果我将目录设置为常数字符串,它确实保存在该路径中。就像我做了下面的事

$target_dir = "Brainplow"

这很好,但我需要根据发送自的参数确定此目录 多部分/表单数据 要求

我的图像目录如下

根目录

子目录

孙子目录

因此,我希望能够传递一个路径(例如:“Brainplow/011113132018112642/”)作为请求的参数

PHP函数应该从参数中获取路径并将图像放在那里

根据我的研究和努力,问题是PHP函数。所以也许不用

$target_dir = $_GET["path"];

我可能不得不使用

$target_dir = $_POST["path"];

但我对PHP知之甚少。但可能还有另一个问题。但我的swift代码运行良好。只是我的形象不在我提供的道路上。

任何帮助都将不胜感激

2 回复 | 直到 7 年前

Awais Fayyaz 7 年前

修改了PHP函数

更改了此行

$target_dir = $_GET["path"];

到

$target_dir = $_POST["path"];

现在它正在工作

Sandeep Kalia 6 年前

使用参数上载多部分图像的完整解决方案

#import Alamofire

func multipartImage(data:Data?, url:String,jsonInput:[String: String], completion: @escaping (_ result: DataResponse<Any>) -> Void) {

        Alamofire.upload(multipartFormData:
            { (multipartFormData) in

                if data != nil {
                    multipartFormData.append(data!, withName:"user_image", fileName:"image.jpg", mimeType:"image/jpeg")
                }else{
                    multipartFormData.append("".data(using: String.Encoding.utf8)!, withName: "user_image")
                }


                for (key, value) in jsonInput
                {
                    multipartFormData.append(value.data(using: String.Encoding.utf8)!, withName: key)
                }
        }, to:url, method: .post, headers: headers)
        { (result) in
            switch result {
            case .success(let upload, _ , _ ):
                upload.uploadProgress(closure:
                    { (progress) in
                        //Print progress
                })

                upload.responseJSON { response in

                    completion(response)

                }
            case .failure(let encodingError):
                print(encodingError.localizedDescription)
                break
            }
        }
    }