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读取和处理XML文件

linq-to-xml linq winforms xml c#

jay_t55 · 技术社区 · 15 年前

我有一个XML文件。其格式如下:

ControlType > Content > LocationX > LocationY > ForeColor/LinkColor > Int > Int > Int > Int

文件示例:

<?xml version="1.0" encoding="utf-8"?>
<cs>
  <Label Content="Double-click to edit." LocationX="583" LocationY="254" A="255" R="255" G="255" B="255" />
  <LinkLabel Content="Double-click to edit." LocationX="613" LocationY="251" A="255" R="0" G="0" B="0" />
</cs>

背景:生成一个XML文件并保存在磁盘上。当用户将XML文档加载到我的应用程序中时,我的应用程序将读取XML文件。对于文档中的foreach控件,它将检索其属性,如下所示:

foreach(Control control in XmlFile)
{
     // get control type
     // get control content
     // get LocationX
     // get LocationY
     // get Color
     // get Int
     // get Int
     // get Int
     // get Int

     // Do something with retrieved data.
}

我已经有了:

OpenFileDialog o = new OpenFileDialog();

o.Filter =
    "T Multimedia Format (*.mf)|*.mf|" +
    "Word Document (*.docx)|*.docx|" +
    "PDF Document (*.pdf)|*.pdf|" +
    "Text FIle (*.txt)|*.txt";
o.Title = "T 11 - Open Document";

using (o)
{
    if (o.ShowDialog() == DialogResult.OK)
    {
        XDocument xdc = XDocument.Load(o.FileName);

        var cs = xdc.Elements("cs");
        foreach (var im in cs)
        {
            if (im.Name == "Label")
            {
                Label label = new Label();
                label.MouseClick += new MouseEventHandler(label_MouseClick);
                label.MouseDown += new MouseEventHandler(label_MouseDown);
                label.MouseMove += new MouseEventHandler(label_MouseMove);
                label.MouseUp += new MouseEventHandler(label_MouseUp);
                label.MouseDoubleClick += new MouseEventHandler(label_MouseDoubleClick);

                label.Text = im.Attribute("Content").Value;

                label.Location = new Point(
                    Convert.ToInt32(im.Attribute("LocationX").Value),
                    Convert.ToInt32(im.Attribute("LocationY").Value));

                label.BackColor = Color.Transparent;
                label.ForeColor = Color.FromArgb(
                    Convert.ToInt32(im.Attribute("A").Value),
                    Convert.ToInt32(im.Attribute("R").Value),
                    Convert.ToInt32(im.Attribute("G").Value),
                    Convert.ToInt32(im.Attribute("B").Value));

                label.AutoSize = true;
                Canvas.Controls.Add(label);

                label.BringToFront();
            }
            else if (im.Name == "LinkLabel")
            {
                LinkLabel link = new LinkLabel();
                link.MouseClick += new MouseEventHandler(link_MouseClick);
                link.MouseDown += new MouseEventHandler(link_MouseDown);
                link.MouseMove += new MouseEventHandler(link_MouseMove);
                link.MouseUp += new MouseEventHandler(link_MouseUp);
                link.MouseDoubleClick += new MouseEventHandler(link_MouseDoubleClick);

                link.Text = im.Attribute("Content").Value;

                link.Location = new Point(
                    Convert.ToInt32(im.Attribute("LocationX").Value),
                    Convert.ToInt32(im.Attribute("LocationY").Value));

                link.BackColor = Color.Transparent;
                link.LinkColor = Color.FromArgb(
                    Convert.ToInt32(im.Attribute("A").Value),
                    Convert.ToInt32(im.Attribute("R").Value),
                    Convert.ToInt32(im.Attribute("G").Value),
                    Convert.ToInt32(im.Attribute("B").Value));

                link.AutoSize = true;
                Canvas.Controls.Add(link);

                link.BringToFront();
            }
        }
    }
}

…上面的代码产生零错误。但是,它就是不起作用。表单上没有显示任何控件。有人知道上面的代码为什么不起作用吗?我怎么能让它起作用呢?

谢谢你的帮助

巴尔

1 回复 | 直到 12 年前

Darin Dimitrov 15 年前

我建议你用一种更通用的方法:

private void Form1_Load(object sender, EventArgs e)
{
    foreach (var controlTag in XDocument.Load("settings.xml").Root.Elements())
    {
        var controlType = Type.GetType(string.Format("System.Windows.Forms.{0}, System.Windows.Forms, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089", controlTag.Name.LocalName), false);
        if (controlType == null || !typeof(Control).IsAssignableFrom(controlType))
        {
            continue;
        }
        var control = (Control)Activator.CreateInstance(controlType);
        control.Text = controlTag.Attribute("Content").Value;
        control.Location = new Point(
            int.Parse(controlTag.Attribute("LocationX").Value),
            int.Parse(controlTag.Attribute("LocationY").Value)
        );
        control.BackColor = Color.Transparent;

        control.MouseClick += mouseClick;
        control.MouseDown += mouseDown;
        control.MouseMove += mouseMove;
        control.MouseUp += mouseUp;
        control.MouseDoubleClick += mouseDoubleClick;

        Controls.Add(control);
    }

}

至于颜色,您可以向XML文件添加一个属性,该属性将指向要设置和使用反射的控件的属性名。例如:

<?xml version="1.0" encoding="utf-8"?>
<cs>
  <Label Content="Double-click to edit." LocationX="583" LocationY="254" A="255" R="255" G="255" B="255" ColorProperty="ForeColor" />
  <LinkLabel Content="Double-click to edit." LocationX="613" LocationY="251" A="255" R="0" G="0" B="0" ColorProperty="LinkColor" />
</cs>

顺便说一下,XAML已经提供了您在这里试图实现的许多功能。当然,它假定的是WPF接口,这可能不是您的情况。