选择
SYS_GUID()
分别(例如,使用CTE,如我的示例所示)并将其值与列连接(我使用L12和L17指示您提到的第12行和第17行)。
SQL> with gujda as
2 (select sys_guid() guj
3 from dual
4 connect by level <= 4
5 )
6 select 'L12_' || g.guj l12,
7 'L17_' || g.guj l17
8 from gujda g;
L12 L17
------------------------------------ ------------------------------------
L12_EFB5A4947D2E4B7BBE6017E57C673ABF L17_EFB5A4947D2E4B7BBE6017E57C673ABF
L12_3E2D5B50D7C44C7FA6073A9F739687CF L17_3E2D5B50D7C44C7FA6073A9F739687CF
L12_724C21F7914B423B8CBDDC6A44AD2016 L17_724C21F7914B423B8CBDDC6A44AD2016
L12_F15D6C9865424E5C8FFFEA9C09DD6D37 L17_F15D6C9865424E5C8FFFEA9C09DD6D37
SQL>