C++链接器错误LNK 2019未解析的外部符号引用在函数中

在本文之后,我试图实现一个智能类

https://www.codeproject.com/Articles/15351/Implementing-a-simple-smart-pointer-in-c

我有一门课叫 人 .

class Person
{
    private:
        char* name;
        int age;
    public:
        Person();
        Person(const char* pName, int pAge);
        ~Person();
        void Display();
};

人cpp

#include<iostream>
#include "Person.h"

Person::Person() : name(nullptr), age(0)
{}

Person::Person(const char* pName, int pAge) 
{
      name = new char[std::strlen(pName) + 1];
      std::strcpy(name, pName);
      age = pAge;
}

Person::~Person()
{}

void Person::Display()
{
     std::cout << "Name is " << name << " and age is " << age << std::endl;
}

参考计数。H

#pragma once
class ReferenceCount
{
    private:
         int count;
    public:
        ReferenceCount();
        ~ReferenceCount();
        void AddRef();
        void DelRef();

};

参考计数。cpp

#include "ReferenceCount.h"

ReferenceCount::ReferenceCount() : count(0)
{}

ReferenceCount::~ReferenceCount()
{}

void ReferenceCount::AddRef()
{
     count++;
}

void ReferenceCount::DelRef()
{
    count--;
}

SmartClass。H

#pragma once
#include "ReferenceCount.h"

template <typename T> class SmartClass
{
   private:
       T* pData;
       ReferenceCount* rc;
   public:
       SmartClass();
       SmartClass(T* data);
       SmartClass(const SmartClass<T>& sp); // copy constructor
      ~SmartClass();
      T& operator*();
      T* operator->();
      SmartClass<T>& operator=(const SmartClass<T>& sp); // copy assignment operator
};

SmartClass。cpp

#include "SmartClass.h"

template <typename T>
SmartClass<T>::SmartClass() : rc(0)
{
    rc = new ReferenceCount();
    rc->AddRef();
}

template <typename T> 
SmartClass<T>::SmartClass(T* data) : pData(data), rc(0)
{
   rc = new ReferenceCount();
   rc->AddRef();
}

template<typename T>
SmartClass<T>::SmartClass(const SmartClass<T>& sp)  // copy constructor
{
  this->pData = sp.pData;
  this->rc = sp.rc;
}

template <typename T>
SmartClass<T>::~SmartClass()
{
  if (rc->DelRef() == 0) 
  {
    delete pData;
    delete rc;
  }
}

template <typename T>
T& SmartClass<T>::operator*()
{
  return *pdata;
}

template<typename T>
T* SmartClass<T>::operator->()
{
  return pData;
}

template <typename T>
SmartClass<T>& SmartClass<T>::operator=(const SmartClass<T>& sp)
{
  if (this != &sp)
  {
     if (rc->DelRef() == 0)
     {
        delete pData;
        delete rc;
     }

     pData = sp.pData;
     rc = sp.rc;
    rc->AddRef();
 }
    return *this;
}

主要的cpp

#include "Person.h"
#include "SmartClass.h"

int main()
{
    SmartClass<Person> p(new Person("Scott", 25));
    return 0;
}

在使用Visual Studio 2017构建程序时,我遇到了以下链接器错误。

LNK2019未解析的外部符号“public:u thiscall SmartClass::SmartClass(class Person*)”(??0$SmartClass@VPerson@@@@QAE@PAVPerson@@@Z) 在函数_main中引用

LNK2019未解析的外部符号“public:u thiscall SmartClass::~SmartClass(void)”(??1$SmartClass@VPerson@@@@QAE@XZ)在函数_main中引用

我在这段代码中做错了什么?你能帮我纠正一下吗?

非常感谢。