Django BooleanField作为单选按钮?

在models.py中,为布尔字段指定“choices”:

BOOL_CHOICES = ((True, 'Yes'), (False, 'No'))

class MyModel(models.Model):
    yes_or_no = models.BooleanField(choices=BOOL_CHOICES)

然后,在forms.py中,为该字段指定RadioSelect小部件:

class MyModelForm(forms.ModelForm):
    class Meta:
        model = MyModel
        widgets = {
            'yes_or_no': forms.RadioSelect
        }

我用SQLite数据库测试了这一点,该数据库还将布尔值存储为1/0值,在没有自定义强制函数的情况下,它似乎工作得很好。

您可以通过覆盖ModelForm中的字段定义来实现这一点:

class MyModelForm(forms.ModelForm):
    boolfield = forms.TypedChoiceField(
                   coerce=lambda x: x == 'True',
                   choices=((False, 'False'), (True, 'True')),
                   widget=forms.RadioSelect
                )

    class Meta:
         model = MyModel

稍微修改一下Daniel Roseman的答案,你可以通过使用int来简洁地解决bool(“False”)=True问题:

class MyModelForm(forms.ModelForm):
    boolfield = forms.TypedChoiceField(coerce=lambda x: bool(int(x)),
                   choices=((0, 'False'), (1, 'True')),
                   widget=forms.RadioSelect
                )

class Meta:
     model = MyModel

class MyModelForm(forms.ModelForm):
    yes_no = forms.BooleanField(widget=RadioSelect(choices=[(True, 'Yes'), 
                                                            (False, 'No')]))

class EmailSettingsForm(ModelForm):

    class Meta:
        model = EmailSetting
        fields = ['setting']
        widgets = {'setting': RadioSelect(choices=[
            (True, 'Keep updated with emails.'),
            (False, 'No, don\'t email me.')             
        ])}

与@eternicode的答案相同,但不修改模型:

class MyModelForm(forms.ModelForm):
    yes_no = forms.RadioSelect(choices=[(True, 'Yes'), (False, 'No')])

    class Meta:
        model = MyModel
        widgets = {'boolfield': yes_no}

我认为这只适用于Django 1.2+

这是一个快速和;使用lambda的脏强制函数,绕过“False”->真正的问题:

...
boolfield = forms.TypedChoiceField(coerce=lambda x: x and (x.lower() != 'false'),
...

由于@Daniel Roseman的回答中存在问题,bool('False')-->没错,所以现在我把两个答案结合在一起,得出一个解决方案。

def boolean_coerce(value):
    # value is received as a unicode string
   if str(value).lower() in ( '1', 'true' ):
       return True
   elif str(value).lower() in ( '0', 'false' ):
       return False
   return None

class MyModelForm(forms.ModelForm):
boolfield = forms.TypedChoiceField(coerce= boolean_coerce,
               choices=((False, 'False'), (True, 'True')),
               widget=forms.RadioSelect
            )

class Meta:
     model = MyModel

def boolean_coerce(value):
    # value is received as a unicode string
    if str(value).lower() in ( '1', 'true' ):
        return True
    elif str(value).lower() in ( '0', 'false' ):
        return False
    return None

另一种解决方案:

from django import forms
from django.utils.translation import ugettext_lazy as _

def RadioBoolean(*args, **kwargs):
    kwargs.update({
        'widget': forms.RadioSelect,
        'choices': [
            ('1', _('yes')),
            ('0', _('no')),
        ],
        'coerce': lambda x: bool(int(x)) if x.isdigit() else False,
    })
    return forms.TypedChoiceField(*args, **kwargs)

django 3.0版本的更新:

BOOLEAN_CHOICES = (('1', 'True label'), ('0', 'False label'))
  # Filtering fields
    True_or_false_question = forms.ChoiceField(
        label="Some Label3",
  # uses items in BOOLEAN_CHOICES
        choices = BOOLEAN_CHOICES,
        widget = forms.RadioSelect
    )

它给出了一个要点按钮列表,我不知道如何让它不这样做