在多个基类之间重载成员函数

基本上,我希望有多个成员函数具有相同的名称,但不同的签名,分布在多个基类中。

例子:

#include <iostream>

struct A
{
    void print(int) { std::cout << "Got an int!" << std::endl; }
};

struct B
{
    void print(double) { std::cout << "Got a double!" << std::endl; }
};

struct C : A, B {};

int main()
{
    C c;
    c.print((int)0);

    return 0;
};

但我在clang上犯了个错误:

main.cpp:18:7: error: member 'print' found in multiple base classes of different types
    c.print((int)0);
      ^
main.cpp:5:10: note: member found by ambiguous name lookup
    void print(int) { std::cout << "Got an int!" << std::endl; }
         ^
main.cpp:10:10: note: member found by ambiguous name lookup
    void print(double) { std::cout << "Got a double!" << std::endl; }

为什么会模棱两可?即使参数数目不同,我也会得到相同的错误。

有什么办法可以让你做出类似的行为吗?