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Mongoose-中间件中找不到模型方法

model mongoose mongodb node.js

Mankind1023 · 技术社区 · 8 年前

有可能我已经精疲力竭了,但我有以下型号:

用户

const mongoose = require('mongoose');
const validate = require('mongoose-validator');
const Post = require('./post');

let UserSchema = mongoose.Schema({
    firstName: { type: String, required: true },
    lastName: { type: String, required: true },
    email: {
        type: String, required: true, lowercase: true, trim: true, unique: true, index: true,
        validate: [validate({ validator: 'isEmail', message: 'Invalid Email!' })]
    },
    posts: [{ type: mongoose.Schema.Types.ObjectId, ref: 'Post' }]
})

module.exports = mongoose.model('User', UserSchema);

帖子

const _ = require('lodash');
const mongoose = require('mongoose');
const User = require('./user');

let PostSchema = mongoose.Schema({
    user: { type: mongoose.Schema.Types.ObjectId, ref: 'User', required: true },
    title: { type: String, required: true },
    body: { type: String, require: true }
})

PostSchema.post('save', async function (next) {
    await User.update({ _id: this.user }, { $push: { posts: this._id } })
    return next();
})

module.exports = mongoose.model('Post', PostSchema);

当尝试添加新的日志时,会运行post save hook,但我得到了错误user.update不是一个函数(findoneandupdate、findone等也是如此)。

我可以从应用程序的其余部分调用user.update,但没有问题,因此不确定这里发生了什么。两个模型在同一目录中。

1 回复 | 直到 8 年前

Neil Lunn 8 年前

你错过的是 post 中间件的第一个参数是“文档”,而不是 next 处理程序:

用户.js

const { Schema } = mongoose = require('mongoose');


const userSchema = new Schema({
  firstName: String,
  lastName: String,
  posts: [{ type: Schema.Types.ObjectId, ref: 'Post' }]
});

后JS

const { Schema } = mongoose = require('mongoose');

const User = require('./user');

const postSchema = new Schema({
  user: { type: Schema.Types.ObjectId, ref: 'User' },
  title: String,
  body: String
});

// note that first argument is the "document" as in "post" once it was created
postSchema.post('save', async function(doc, next) {
  await User.update({ _id: doc.user._id },{ $push: { posts: doc._id } });
  next();
});

索引.js

const { Schema } = mongoose = require('mongoose');

const User = require('./user');
const Post = require('./post');

const uri = 'mongodb://localhost/posttest';

mongoose.set('debug', true);
mongoose.Promise = global.Promise;

const log = data => console.log(JSON.stringify(data, undefined, 2));

(async function() {

  try {

    const conn = await mongoose.connect(uri);

    await Promise.all(Object.entries(conn.models).map(([k,m]) => m.remove()));

    let user = await User.create({ firstName: 'Ted', lastName: 'Logan' });

    let post = new Post({ user: user._id, title: 'Hi', body: 'Whoa!' });
    post = await post.save();

    mongoose.disconnect();

  } catch(e) {
    console.error(e)
  } finally {
    process.exit()
  }

})()

Mongoose: users.remove({}, {})
Mongoose: posts.remove({}, {})
Mongoose: users.insertOne({ posts: [], _id: ObjectId("5b0217001b5a55208150cc9b"), firstName: 'Ted', lastName: 'Logan', __v: 0 })
Mongoose: posts.insertOne({ _id: ObjectId("5b0217001b5a55208150cc9c"), user: ObjectId("5b0217001b5a55208150cc9b"), title: 'Hi', body: 'Whoa!', __v: 0 })
Mongoose: users.update({ _id: ObjectId("5b0217001b5a55208150cc9b") }, { '$push': { posts: ObjectId("5b0217001b5a55208150cc9c") } }, {})

显示更新以正确的细节触发。

在好的设计中,你真的应该避免这种情况,只需将 posts 数组来自 User 模型。您可以使用 virtual 相反:

userSchema.virtual('posts', {
  ref: 'Post',
  localField: '_id',
  foreignField: 'user'
})

或者只是通过 $lookup :

User.aggregate([
   { "$match": { "_id": userId } }
   { "$lookup": {
     "from": Post.collection.name,
     "localField": "_id",
     "foreignField": "user",
     "as": "posts"
   }}
])

存储和维护相关数组 ObjectId 值“on the parent”是一种“反模式”,会导致不必要的开销,例如在只需要“one”的两个地方编写。

此外,一般情况下,您应该选择嵌入“first”,并且仅在应用程序的使用模式实际需要时才考虑“引用”。简单地使用一个数据库引擎复制RDBMS的相同模式并不是利用它的最佳方法。