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SQL Server 2008:统计多个日期范围中的键数

sql-server-2008 sql-server sql

user327301 · 技术社区 · 15 年前

SQL Server 2008再次出现。我有一把钥匙 pt_id 和日期时间列 order_dts 对于每个ID,我要计算1996-2008年间每年的密钥数,并返回八个结果-每年一个计数。一年内

SELECT COUNT pm.pt_id AS '1996'
FROM dm.medications pm
WHERE (pm.order_dts BETWEEN '1/1/1996' and '12/31/1996')

是的,但是我怎么能这么多年不做像八个不同的问题这样荒谬的事情呢?

谢谢您!

2 回复 | 直到 15 年前

D'Arcy Rittich 15 年前

SELECT COUNT(*),  Year(pm.order_dts) as Year
FROM dm.medications pm
WHERE Year(pm.order_dts) between 1996 AND 2008
group by Year(pm.order_dts)

如果您希望将所有内容都放在一行中,可以执行以下操作:

SELECT 
    sum(case when Year(pm.order_dts) = 1996 then 1 end) as Count1996,
    sum(case when Year(pm.order_dts) = 1997 then 1 end) as Count1997,
    sum(case when Year(pm.order_dts) = 1998 then 1 end) as Count1998,
    sum(case when Year(pm.order_dts) = 1999 then 1 end) as Count1999,
    sum(case when Year(pm.order_dts) = 2000 then 1 end) as Count2000,
    sum(case when Year(pm.order_dts) = 2001 then 1 end) as Count2001,
    sum(case when Year(pm.order_dts) = 2002 then 1 end) as Count2002,
    sum(case when Year(pm.order_dts) = 2003 then 1 end) as Count2003,
    sum(case when Year(pm.order_dts) = 2004 then 1 end) as Count2004,
    sum(case when Year(pm.order_dts) = 2005 then 1 end) as Count2005,
    sum(case when Year(pm.order_dts) = 2006 then 1 end) as Count2006,
    sum(case when Year(pm.order_dts) = 2007 then 1 end) as Count2007,
    sum(case when Year(pm.order_dts) = 2008 then 1 end) as Count2008
FROM dm.medications pm

Joe 15 年前

select count(pm.pt_id) as count, datepart(yy, pm.order_dts) as year
from dm.medications pm
WHERE (pm.order_dts BETWEEN '1/1/1996' and '12/31/1996')
group by datepart(yy, pm.order_dts)

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