在co例程中从pudb启动IPython交互式shell失败

我真的很喜欢 pudb 与 IPython 我已经 多年来成功调试python代码。

# test1.py
import time

def do_something():
    import pudb
    pudb.set_trace()

    sleep(1)
    return 1

do_something()

如果你执行 python test1.py ,开始时按 ! 这个

但是,如果你在一个共同例程中设置了一个跟踪,pudb就会毫无问题地启动, 你甚至可以踏进 await some_async_call() 要启动交互式shell并按 ! 有一个错误。福克斯示例:

# test2.py
import asyncio

async def do_something():
    import pudb
    pudb.set_trace()

    await asyncio.sleep(1)

    return 1

asyncio.run(do_something())

$ python test2.py

pudb starts and halts before await asyncio.sleep(1), now press !

Hit Ctrl-D to return to PuDB.

In [1]:
Traceback (most recent call last):
  File "test2.py", line 11, in <module>
    asyncio.run(do_something())
  File "/home/shaoran/anaconda/py3/envs/ivct/lib/python3.8/asyncio/runners.py", line 43, in run
    return loop.run_until_complete(main)
  File "/home/shaoran/anaconda/py3/envs/ivct/lib/python3.8/asyncio/base_events.py", line 599, in run_until_complete
    self.run_forever()
  File "test2.py", line 7, in do_something
    await asyncio.sleep(1)
  File "test2.py", line 7, in do_something
    await asyncio.sleep(1)
...
  File "/home/shaoran/anaconda/py3/envs/ivct/lib/python3.8/asyncio/base_events.py", line 554, in run_forever
    raise RuntimeError('This event loop is already running')
RuntimeError: This event loop is already running
Task was destroyed but it is pending!
task: <Task pending name='Task-5' coro=<Renderer.wait_for_cpr_responses.<locals>.wait_for_timeout() running at /home/shaoran/anaconda/py3/envs/ivct/lib/python3.8/site-packages/prompt_toolkit/renderer.py:505> wait_for=<Future pending cb=[<TaskWakeupMethWrapper object at 0x7fe05cd42fd0>()]>>

我怀疑这是IPython的问题,因为如果我将shell从 IPython到 bpython 然后按 ,然后启动bpython交互式shell 没有问题。我一直在寻找解决办法,但似乎 请求github #12028 , #12140 和 #12141 , 这似乎与此有关,但我不知道是不是真的,或者是否

所以我的问题是:有人能重现这个错误吗?这是布丁还是伊普顿 错误?

我使用从anaconda4.8.3(linux 64位)和IPython安装的python3.8.1 7.13.0(安装 conda install ipython -c conda-forge 通过安装时适用 pip ).