定义要与IN运算符(T-SQL)一起使用的变量

DECLARE @MyList TABLE (Value INT)
INSERT INTO @MyList VALUES (1)
INSERT INTO @MyList VALUES (2)
INSERT INTO @MyList VALUES (3)
INSERT INTO @MyList VALUES (4)

SELECT *
FROM MyTable
WHERE MyColumn IN (SELECT Value FROM @MyList)

DECLARE @mylist TABLE (Id int)
INSERT INTO @mylist
SELECT id FROM (VALUES (1),(2),(3),(4),(5)) AS tbl(id)

SELECT * FROM Mytable WHERE theColumn IN (select id from @mylist)

有两种方法可以处理TSQL查询的动态csv列表:

1) 使用内部选择

SELECT * FROM myTable WHERE myColumn in (SELECT id FROM myIdTable WHERE id > 10)

DECLARE @sql varchar(max)  
declare @list varchar(256)  
select @list = '1,2,3'  
SELECT @sql = 'SELECT * FROM myTable WHERE myColumn in (' + @list + ')'

exec sp_executeSQL @sql

DECLARE @list TABLE (Id INT)

INSERT INTO @list(Id)
SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4


SELECT
    * 
FROM 
    myTable
    JOIN @list l ON myTable.myColumn = l.Id

SELECT
    * 
FROM 
    myTable
WHERE
    myColumn IN (SELECT Id FROM @list)

CREATE function [dbo].[list_to_table] (@list varchar(4000))
returns @tab table (item varchar(100))
begin

if CHARINDEX(',',@list) = 0 or CHARINDEX(',',@list) is null
begin
    insert into @tab (item) values (@list);
    return;
end


declare @c_pos int;
declare @n_pos int;
declare @l_pos int;

set @c_pos = 0;
set @n_pos = CHARINDEX(',',@list,@c_pos);

while @n_pos > 0
begin
    insert into @tab (item) values (SUBSTRING(@list,@c_pos+1,@n_pos - @c_pos-1));
    set @c_pos = @n_pos;
    set @l_pos = @n_pos;
    set @n_pos = CHARINDEX(',',@list,@c_pos+1);
end;

insert into @tab (item) values (SUBSTRING(@list,@l_pos+1,4000));

return;
end;

不使用like,而是与函数返回的表进行内部联接:

select * from table_1 where id in ('a','b','c')

select * from table_1 a inner join [dbo].[list_to_table] ('a,b,c') b on (a.id = b.item)

在一个没有索引的1M记录表中,第二个版本花费了大约一半的时间。。。

DECLARE @myList TABLE (Id BIGINT) INSERT INTO @myList(Id) VALUES (1),(2),(3),(4);
select * from myTable where myColumn in(select Id from @myList)

请注意,对于长列表或生产系统,不建议使用这种方法,因为它可能比简单的方法慢得多 IN 类运算符 someColumnName in (1,2,3,4)

从SQL2017开始,您可以使用 STRING_SPLIT 这样做:

declare @myList nvarchar(MAX)
set @myList = '1,2,3,4'
select * from myTable where myColumn in (select value from STRING_SPLIT(@myList,','))

• 动态生成的查询(sp\u executesql)
• 表类型变量(最接近列表的东西)

@LukeH稍有改进,无需重复“INSERT INTO”: 和@realPT的答案-无需选择:

DECLARE @MyList TABLE (Value INT) 
INSERT INTO @MyList VALUES (1),(2),(3),(4)

SELECT * FROM MyTable
WHERE MyColumn IN (SELECT Value FROM @MyList)

DECLARE @InList varchar(255) = 'This;Is;My;List';

WITH InList (Item) AS (
    SELECT value FROM STRING_SPLIT(@InList, ';')
)

SELECT * 
FROM [Table]
WHERE [Item] IN (SELECT Tag FROM InList)

如果要在不使用第二个表的情况下执行此操作,可以与CAST进行类似的比较:

DECLARE @myList varchar(15)
SET @myList = ',1,2,3,4,'

SELECT *
FROM myTable
WHERE @myList LIKE '%,' + CAST(myColumn AS varchar(15)) + ',%'

用逗号包围列匹配和每个唯一值将确保精确匹配。否则,将在包含',4,2,15,'的列表中找到值1

正如之前没有人提到的,从SQLServer2016开始,您还可以使用json数组和 OPENJSON (Transact-SQL)

declare @filter nvarchar(max) = '[1,2]'

select *
from dbo.Test as t
where
    exists (select * from openjson(@filter) as tt where tt.[value] = t.id)

你可以试一下 sql fiddle demo

Search list of values and range in SQL using WHERE IN clause with SQL variable?

这一个使用PATINDEX将表中的id与非数字分隔的整数列表进行匹配。

-- Given a string @myList containing character delimited integers 
-- (supports any non digit delimiter)
DECLARE @myList VARCHAR(MAX) = '1,2,3,4,42'

SELECT * FROM [MyTable]
    WHERE 
        -- When the Id is at the leftmost position 
        -- (nothing to its left and anything to its right after a non digit char) 
        PATINDEX(CAST([Id] AS VARCHAR)+'[^0-9]%', @myList)>0 
        OR
        -- When the Id is at the rightmost position
        -- (anything to its left before a non digit char and nothing to its right) 
        PATINDEX('%[^0-9]'+CAST([Id] AS VARCHAR), @myList)>0
        OR
        -- When the Id is between two delimiters 
        -- (anything to its left and right after two non digit chars)
        PATINDEX('%[^0-9]'+CAST([Id] AS VARCHAR)+'[^0-9]%', @myList)>0
        OR
        -- When the Id is equal to the list
        -- (if there is only one Id in the list)
        CAST([Id] AS VARCHAR)=@myList

• %(通配符)将匹配任何零个或多个字符的字符串
• [^0-9]将匹配任何非数字字符
• PATINDEX是一个SQL标准函数,返回模式在字符串中的位置

DECLARE @StatusList varchar(MAX);
SET @StatusList='1,2,3,4';
DECLARE @Status SYS_INTEGERS;
INSERT INTO  @Status 
SELECT Value 
FROM dbo.SYS_SPLITTOINTEGERS_FN(@StatusList, ',');
SELECT Value From @Status;

看一看 sp_executeSQL