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Postgres SQL:如何在此SQL中进行分组

group-by postgresql database sql

anjanb · 技术社区 · 14 年前

下面的SQL从审计表family_Audit和family_address_Audit生成报告。

(SELECT fam.familyserialno, fam.familyname, addr.housenumber, addr.address1,
        COALESCE(fam.operation, addr.operation) op,
        COALESCE(fam.username, addr.username) usr,
        COALESCE(fam.adddate, addr.adddate) add_date,
        (SELECT r.userrolename 
           FROM userrole_master r, user_master u 
          WHERE u.loginid=COALESCE(fam.username, addr.username) AND r.userrole_id=u.userrole_id) rolename
  FROM family_audit fam
       INNER JOIN family_address_audit addr USING(txid, family_id)
WHERE (fam.node_id = 8) AND (fam.familyserialno >=1 and fam.familyserialno <=5)
)
UNION
(SELECT fam.familyserialno, fam.familyname,
        addr.housenumber, addr.address1,
        COALESCE(fam.operation, addr.operation) op,
        COALESCE(fam.username, addr.username) usr,
        COALESCE(fam.adddate, addr.adddate) add_date,
        (SELECT r.userrolename 
           FROM userrole_master r, user_master u 
          WHERE u.loginid=COALESCE(fam.username, addr.username) AND r.userrole_id=u.userrole_id) rolename
   FROM family_audit fam
        FULL OUTER JOIN family_address_audit addr USING(txid, family_id)
  WHERE ((fam.familyserialno IS NULL and addr.family_id in 
             (select family_id 
                from family 
               where familyserialno >=1 and familyserialno <=5 and node_id =8)) 
         OR ((addr.family_id IS NULL) and ((fam.familyserialno >=1 and fam.familyserialno <=5) and fam.node_id=8) ) )
)
ORDER BY add_date DESC;

“above”SQL的典型输出如下

 familyserialno | familyname | housenumber |  address1  | op |  usr  |        add_date         | rolename
----------------+------------+-------------+------------+----+-------+-------------------------+----------
              3 | thirda     |             |            | U  | admin | 2010-11-24 15:29:34.312 | admin
                |            | 34324       | sdfdsfdsf  | U  | admin | 2010-11-24 15:28:42.314 | admin
              3 | third      |             |            | I  | admin | 2010-11-24 15:28:34.576 | admin
                |            | 333         | sdfdsf     | U  | admin | 2010-11-24 15:18:57.129 | admin
              2 | aSecond    |             |            | I  | admin | 2010-11-24 14:58:15.477 | admin
              1 | anjanFirst | anjanFirst  | anjanFirst | I  | admin | 2010-11-24 14:12:35.477 | admin

======================

我想按fam.familyseriano对输出进行分组。因此,我修改了上面的SQL如下;但是,这会导致一个错误(在最后)

SELECT * from 
((SELECT fam.familyserialno, fam.familyname, addr.housenumber, addr.address1,
        COALESCE(fam.operation, addr.operation) op,
        COALESCE(fam.username, addr.username) usr,
        COALESCE(fam.adddate, addr.adddate) add_date,
        (SELECT r.userrolename 
           FROM userrole_master r, user_master u 
          WHERE u.loginid=COALESCE(fam.username, addr.username) AND r.userrole_id=u.userrole_id) rolename
  FROM family_audit fam
       INNER JOIN family_address_audit addr USING(txid, family_id)
WHERE (fam.node_id = 8) AND (fam.familyserialno >=1 and fam.familyserialno <=5)
)
UNION
(SELECT fam.familyserialno, fam.familyname,
        addr.housenumber, addr.address1,
        COALESCE(fam.operation, addr.operation) op,
        COALESCE(fam.username, addr.username) usr,
        COALESCE(fam.adddate, addr.adddate) add_date,
        (SELECT r.userrolename 
           FROM userrole_master r, user_master u 
          WHERE u.loginid=COALESCE(fam.username, addr.username) AND r.userrole_id=u.userrole_id) rolename
   FROM family_audit fam
        FULL OUTER JOIN family_address_audit addr USING(txid, family_id)
  WHERE ((fam.familyserialno IS NULL and addr.family_id in 
             (select family_id 
                from family 
               where familyserialno >=1 and familyserialno <=5 and node_id =8)) 
         OR ((addr.family_id IS NULL) and ((fam.familyserialno >=1 and fam.familyserialno <=5) and fam.node_id=8) ) )
))
GROUP BY 1 
ORDER BY 7 DESC;

错误:中的子查询必须具有别名第2行:((选择fam.familyserialno、fam.familyname、addr.houseNumber。。。 ^ 提示:例如,FROM(SELECT…[AS]foo。

我该怎么解决?我们真的需要所有的行按fam.familyseriano分组。

非常感谢你,

附言:我们正在使用Postgres8.4.4。

1 回复 | 直到 14 年前

jmz 14 年前

您需要对子查询进行别名,如下所示:

 SELECT * FROM ((SELECT ...) UNION (SELECT ...)) AS foo GROUP BY 1 ORDER BY 7 DESC;

在这里 foo 是子查询的别名。