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PHP-无法从此Json响应中提取电子邮件

json php

-1

TSCAmerica.com · 技术社区 · 8 年前

array(85) {
  ["attributes"]=>
  array(2) {
    ["type"]=>
    string(7) "Contact"
    ["url"]=>
    string(56) "/services/data/v20.0/sobjects/Contact/000002HQRBYAA5"
  }
  ["Id"]=>
  string(18) "0030002HQRBYAA5"
  ["IsDeleted"]=>
  bool(false)
  ["Email"]=>
  string(28) "t@stics.com"

}
array(85) {
  ["attributes"]=>
  array(2) {
    ["type"]=>
    string(7) "Contact"
    ["url"]=>
    string(56) "/services/data/v20.0/sobjects/Contact/0002HQRBTAA5"
  }
  ["Id"]=>
  string(18) "0000002HQRBTAA5"
  ["IsDeleted"]=>
  bool(false)
  ["Email"]=>
  string(35) "test@gmail.com"

}

我在PHP中尝试的是

$accID="3234234";
$url1 = "$instance_url/services/data/v20.0/sobjects/Contact/$accID";
$curl1 = curl_init($url1);

curl_setopt($curl1, CURLOPT_HEADER, false);
curl_setopt($curl1, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl1, CURLOPT_HTTPHEADER,
array("Authorization: OAuth $access_token"));
$json_response1 = curl_exec($curl1);


$status = curl_getinfo($curl1, CURLINFO_HTTP_CODE);
curl_close($curl1);


$objContact = json_decode($json_response1, TRUE);
//var_dump($objContact);

for($i=0; $i<count($objContact['attributes']); $i++) {
    echo "Contact email is " . $objContact['Email'][$i] . "<BR>";

}

2 回复 | 直到 8 年前

1

3

AbraCadaver 8 年前

您有一个数组,每个数组都有一个 Email 键,所以很简单:

foreach($objContact as $data){
    echo $data['Email'] . '<br>';
}

2

1

mega6382 8 年前

试试这个 foreach 改为循环:

foreach($objContact as $contact)
{
    echo "Contact email is " . $contact['Email'] . "<br>";
}

或与 for 循环如下:

for($i=0; $i<count($objContact); $i++)
{
    echo "Contact email is " . $objContact[$i]['Email'] . "<BR>";
}