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如何在CloudFormation中使用代码构建的输出工件?

amazon-cloudformation aws-codebuild aws-codepipeline amazon-web-services

mth · 技术社区 · 9 年前

所以我有一个相当简单的堆栈,我正试图设置一个单一的Lambda函数订阅的SNS主题组成。我希望将代码管道分为三个阶段:源代码(GitHub)->构建(CodeBuild)->部署(CloudFormation)。

基本上,我应该在 Code:

template.yml:

AWSTemplateFormatVersion: 2010-09-09
Resources:
  SNSTopic:
    Type: 'AWS::SNS::Topic'
    Properties:
      Subscription:
        - Endpoint: !GetAtt
            - LambdaFunction
            - Arn
          Protocol: lambda
  LambdaFunction:
    Type: 'AWS::Lambda::Function'
    Properties:
      Runtime: python3.6
      Handler: main.lamda_handler
      Timeout: '10'
      Role: !GetAtt
        - LambdaExecutionRole
        - Arn
      Code:
        ZipFile: >
          def lambda_handler(event, context):
            print(event)
            return 'Hello, world!'
  LambdaExecutionRole:
    Type: 'AWS::IAM::Role'
    Properties:
      AssumeRolePolicyDocument:
        Version: 2012-10-17
        Statement:
          - Effect: Allow
            Principal:
              Service:
                - lambda.amazonaws.com
            Action:
              - 'sts:AssumeRole'
      ManagedPolicyArns:
        - 'arn:aws:iam::aws:policy/service-role/AWSLambdaBasicExecutionRole'
  LambdaInvokePermission:
    Type: 'AWS::Lambda::Permission'
    Properties:
      FunctionName: !GetAtt
        - LambdaFunction
        - Arn
      Action: 'lambda:InvokeFunction'
      Principal: sns.amazonaws.com
      SourceArn: !Ref SNSTopic

version: 0.2
phases:
  install:
    commands:
      - pip install -r requirements.txt -t libs
artifacts:
  type: zip
  files:
    - template.yml
    - main.py
    - lib/*

3 回复 | 直到 9 年前

mth 9 年前

由于AWS的支持,最终找到了解决方案。首先,我将这个JSON放在CodePipeline中CloudFormation部署步骤的参数覆盖中:

{
  "buildBucketName" : { "Fn::GetArtifactAtt" : ["MyAppBuild", "BucketName"]},
  "buildObjectKey" : { "Fn::GetArtifactAtt" : ["MyAppBuild", "ObjectKey"]}
}

然后将我的CF模板更改为:

AWSTemplateFormatVersion: 2010-09-09
Parameters:
  buildBucketName:
    Type: String
  buildObjectKey:
    Type: String

  Resources:
    ...
    LambdaFunction:
        ...
        Code:
            S3Bucket: !Ref buildBucketName
            S3Key: !Ref buildObjectKey

这会将CodeBuild输出的输出工件bucket名称和对象键作为参数传递给CF,这样它就可以在S3中动态获取输出工件的位置,而无需硬编码任何内容,从而使模板方式更具可移植性。

Alex Nelson 9 年前

您的代码构建应该将zip文件放到S3存储桶中。因此,在LambdaFunction资源的代码部分,您可以指向它。

Code:
   S3Bucket: the_bucket_where_CodeBuild_dropped_your_zip
   S3Key: the_name_of_the_zip_file_dropped

你不需要“ZipFile”:

Neil McGuigan 6 年前

project_root/
  template.yaml
  buildspec.yaml
  my_lambda/
    my_lambda.py
    requirements.txt

template.yaml:

Transform: AWS::Serverless-2016-10-31

Resources:
  MyLambda:
    Type: AWS::Serverless::Function
    Properties:
      Handler: my_lambda.lambda_handler
      CodeUri: my_lambda/
      Runtime: python3.8

version: 0.2

phases:
  install:
    runtime-versions:
      python: 3.8
    commands:
      - pip install aws-sam-cli
  build:
    commands:
      - sam build
      - sam package --s3-bucket mybucket --s3-prefix sam | sam deploy -t /dev/stdin --stack-name FOOSTACK --capabilities CAPABILITY_IAM

笔记:

sam build 将 pip install requirements.txt
sam package 将压缩您的lambda,并用其内容的md5命名,然后为您上传到S3(仅当它已更改时)
sam deploy