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PHP循环#到100,然后再循环另一个#

php

0

SBB · 技术社区 · 8 年前

我正在研究一个快速函数,它将接受一个数字 $max 如果它在下面 100 ,计数依据 5's 高达 $最大值 .

如果 $最大值 大于 100 ,它按5计,直到 100 ,然后按25秒计数,直到命中 $最大值 .

例子:

public function getDenominations($max)
{
    $start = 20;
    $output = [];

    // If max is less than 100, count by 5's
    if($max <= 100 ){
        for($i = $start; $i <= $max; $i += 5) {
            array_push($output, $i);
        }
        return $output;
    // Max is greater than 100, count by 5's up to 100, then by 25's
    }else{
        for($i = $start; $i <= $max; $i += 25) {
            array_push($output, $i);
        }
        return $output;
    }

}

预期输出w/$最大值(&L);100:

5,10,15,20,25,....100

预计产量w/$最大值>100:

5,10,15,20,25,....100,125,150,175,200

我的问题是 $max > 100 ,我被卡住了,首先让它做正常的+5计数,然后是+25计数。目前,它只在25岁开始。

电流输出时间 $max = 500 :

Array ( [0] => 20 [1] => 45 [2] => 70 [3] => 95 [4] => 120 [5] => 145 [6] => 170 [7] => 195 [8] => 220 [9] => 245 [10] => 270 [11] => 295 [12] => 320 [13] => 345 [14] => 370 [15] => 395 [16] => 420 [17] => 445 [18] => 470 [19] => 495 )

预计20-100(到5),然后100-500(到25)。

4 回复 | 直到 8 年前

1

OptimusCrime 8 年前

我已经简化了你的代码。这不需要两个循环,只需保持循环,并用(5或25)更改当前值的增加量,直到达到最大值。

例如如下所示:

$max = 130;
$output = [];
$current = 0;

// Keep looping until we hit max, or break out of the loop
while ($current <= $max) {
    // Find out if we should increase the current value with 5 or 25
    if ($current < 100) {
        $current += 5;
    }
    else {
        $current += 25;
    }

    // Make sure we do not add anything above the current max (e.g. max = 120, current = 110 + 25 = 135)
    if ($current > $max) {
        break;
    }

    // Add the current value to the output array
    $output[] = $current;
}

print_r($output);

输出

Array 
( 
    [0] => 5 
    [1] => 10 
    [2] => 15 
    [3] => 20 
    [4] => 25 
    [5] => 30 
    [6] => 35 
    [7] => 40 
    [8] => 45 
    [9] => 50 
    [10] => 55 
    [11] => 60 
    [12] => 65 
    [13] => 70 
    [14] => 75 
    [15] => 80 
    [16] => 85 
    [17] => 90 
    [18] => 95 
    [19] => 100 
    [20] => 125 
)

Try it online here

2

0

developer 8 年前

像这样-在javascript中?

max = 200
for (i = 1; i < max; i++) {
    out = i * 5;
    console.log(out <= 100 ? out : (i * 5 * 5) - 400);
}

5
10
15
20
25
30
35
40
45
50
55
60
65
70
75
80
85
90
95
100
125
150
175
200
225
250
275
300
325
350
375
400
425
450
475
500
525
550
575
600
625
650
675
700

3

0

Hariprasad S H 8 年前

function getDenominations($max)
{
    $start = 20;
    $output = [];
    $incr = 5;
    $flag = false;

    for ($i = $start; $i <= $max; $i += $incr) {
        array_push($output, $i);

        if( $i >= 100 && $flag === false) {
            $incr = 25;
            $flag = true;
        }

    }
    return $output;
}

print_r(getDenominations(200));

输出

Array
(
[0] => 20
[1] => 25
[2] => 30
[3] => 35
[4] => 40
[5] => 45
[6] => 50
[7] => 55
[8] => 60
[9] => 65
[10] => 70
[11] => 75
[12] => 80
[13] => 85
[14] => 90
[15] => 95
[16] => 100
[17] => 125
[18] => 150
[19] => 175
[20] => 200
)

4

0

axiac 8 年前

您需要的功能可以简单编写为:

function getDenominations($max)
{
    $start = 20;
    $output = [];

    // Count by 5 from $start to 100 or $max, whichever is smaller
    for ($i = $start; $i <= min($max, 100); $i += 5) {
        $output[] = $i;
    }

    // Continue counting by 25 from 125 to $max, if $max is large enough
    for ($i = 125; $i <= $max; $i += 25) {
        $output[] = $i;
    }

    return $output;
}