获取匿名用户的用户实例

我的symfony项目设置得非常整洁,但我一直在努力解决这一点。

App/Entity/User 类,用于从数据库填充用户信息

class User implements AdvancedUserInterface, \Serializable
{
    public function __construct()
    {
        $this->forumPermission = new ArrayCollection();
        $this->activities = new ArrayCollection();
    }

    /**
     * @ORM\Id
     * @ORM\Column(type="integer")
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    private $id;
    /**
     * @ORM\Column(
     *     type="string",
     *     name="salt",
     *     length=32
     * )
     */
    private $salt = "";
    /**
     * @ORM\Column(
     *     type="string",
     *     length=75,
     *     name="user_name"
     * )
     * @Assert\NotBlank(
     *     message="De gebruikersnaam moet ingevuld zijn"
     * )
     */
    private $username;
    // ...
}

并在security.yaml中正确链接

security:
    # https://symfony.com/doc/current/book/security.html#where-do-users-come-from-user-providers
    providers:
        db_provider:
            entity:
                class: App\Entity\User
                property: username

我觉得方便的是匿名用户可以拥有自己的用户实例,但是 $this->getUser() === null . 我明白为什么,但我很固执:

abstract class BaseController extends Controller
{
    protected $logger = null;
    protected $globals = null;
    protected $translator = null;
    protected $security = null;
    /* @var $currentUser User */
    protected $currentUser = null;

    public function __construct(
        Globals $globals,
        LoggerInterface $logger,
        TranslatorInterface $translator,
        Security $security
    ) {
        $this->logger = $logger;
        $this->globals = $globals;
        $this->translator = $translator;
        $this->currentUser = $security->getUser();
    }

    protected function getUser() {
        if (!$this->currentUser instanceof User) {
            /* @var $anonForumPerm ForumPermission */
            $anonForumPerm = $this->getDoctrine()->getRepository(ForumPermission::class)->find(5);
            $this->currentUser = new User();
            $this->currentUser->setName('Anonymous')
                ->setSurname('User')
                ->setUsername('anon.')
                ->setForumPermission($anonForumPerm)
            ;
        }
        return $this->currentUser;
    }
    // ...
}

这似乎管用,但我现在唯一的问题是 app.user 仍然是空的。

有办法推吗 $this->currentUser 应用程序用户 在树枝上?

我的理论是,我想在 应用程序用户 或者 IS_AUTHENTICATED_FULLY

如有额外意见,将不胜感激