用特定类别替换ul标签

我确信这是一份副本,但无论如何,这里是如何处理的 DOM

$dom = new DOMDocument;                          // init new DOMDocument
$dom->loadHTML($html);                           // load HTML into it
$xpath = new DOMXPath($dom);                     // create a new XPath
$nodes = $xpath->query('//ul[@class="level0"]'); // Find all UL with class
foreach($nodes as $node) {                       // Iterate over found elements
    $node->parentNode->removeChild($node);       // Remove UL Element
}
echo $dom->saveHTML();                           // output cleaned HTML

尝试/mis而不是/iu

您的代码工作得很好-除了您将$\u菜单作为字符串传递,该字符串包含的字符不是您进行preg\u替换时使用的字符,尽管事实上它看起来很好。字符串中还包含制表符、分隔符和空格,这些都是regex所不需要的。您可以使用以下方法解决此问题:

(例如)

$_menu='<ul>
    <li>Test
         <ul class="level0">
           ...
         </ul>
     </li>
</ul>
';


$breaks = array("
", "\n", "\r", "chr(13)", "\t", "\0", "\x0B");
$_menu=str_replace($breaks,"",$_menu);

$_menu = preg_replace('/<ul class="level0">(.*)<\/ul>/iU', "", $_menu); 

尝试

$str ='<ul>
    <li>Test
         <ul class="level0">
          tsts
         </ul>
     </li>
</ul>
';
//echo '<pre>';
$str = preg_replace(array("/(\s\/\/.*\\n)/","/(\\t|\\r|\\n)/",'/<!--(.*)-->/Uis','/>\\s+</'),array("","","",'><'),$str);
echo preg_replace('/<ul class="level0">(.*)<\/li>/',"</li>",trim($str));