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Java:在新行开始处匹配重复字符并替换为相同数量的替代字符

whitespace regex java

0

Richard H · 技术社区 · 15 年前

我有一个包含许多行的纯文本文件(新行字符是 \n \\s . 我想替换每一个 \\s公司 具有  

This is a line with no white space at the beginning
  This is a line with 2 whitespace characters at the beginning
    This is a line with 4 whitespace at the beginning

转换为:

This is a line with no white space at the beginning
&nbsp;&nbsp;This is a line with two whitespace characters at the beginning
&nbsp;&nbsp;&nbsp;&nbsp;This is a line with 4 whitespace at the beginning

有什么建议吗?

谢谢

3 回复 | 直到 15 年前

1

5

Alan Moore Chris Ballance 15 年前

text = text.replaceAll("(?m)(?:^|\\G) ", "&nbsp;");

^ 在多行模式下,匹配行首。
\G

如果一次处理一行,可以将regex缩短为 "\\G " .

2

1

Jim Garrison 15 年前

String line;
StringBuilder buf = new StringBuilder();
int i;
for (i=0; i<line.length(); i++)
{
    if (line.charAt(i) == ' ')
        buf.append("&nbsp;");
    else
        break;
}
if (i < line.length()) buf.append(line.substr(i));
line = buf.toString();

3

1

user500074 user500074 15 年前

BufferedReader reader = new BufferedReader(new FileReader("filename"));
String line;
StringBuffer buffer;
while ((line = reader.readLine()) != null) {
  buffer = new StringBuffer();
  int index = line.indexOf(line.trim());
  for (int i = 0; i < index; i++) {
    buffer.append("&nbsp;");
  }

  buffer.append(line.subString(index) + "\n"); 
  System.out.println(buffer.toString()); 
} 
reader.close();

//这里还有一些清理代码