透视查询在T-SQL中不包含2个或更多透视子句,请参阅
FROM - Using PIVOT and UNPIVOT
example here
).
就我个人而言,我会选择一种更传统的透视查询风格,它只使用
GROUP BY
case expressions
必要时(在“pivot”被添加到SQL之前我们一直必须使用的样式)
SELECT
[Facility]
, [Job_Code]
, SUM(CASE WHEN Pay_ClassHrs = 'PBS_Hrs' THEN Pay_ClassHrs END) AS x
, SUM(CASE WHEN Pay_ClassHrs = 'POT_Hrs' THEN Pay_ClassHrs END) AS x
, SUM(CASE WHEN Pay_ClassHrs = 'PED_Hrs' THEN Pay_ClassHrs END) AS x
, SUM(CASE WHEN Pay_ClassHrs = 'POR_Hrs' THEN Pay_ClassHrs END) AS x
, SUM(CASE WHEN Pay_ClassHrs = 'Agency_Hrs' THEN Pay_ClassHrs END) AS x
, SUM(CASE WHEN Pay_ClassHrs = 'PWH_Hrs' THEN Pay_ClassHrs END) AS x
, SUM(CASE WHEN Pay_ClassHrs = 'Sick_Hrs' THEN Pay_ClassHrs END) AS x
, SUM(CASE WHEN Pay_ClassHrs = 'PTO_Hrs' THEN Pay_ClassHrs END) AS x
, SUM(CASE WHEN Pay_ClassHrs = 'Holiday_Hrs' THEN Pay_ClassHrs END) AS x
, SUM(CASE WHEN Pay_ClassHrs = 'PJB_Hrs' THEN Pay_ClassHrs END) AS x
, SUM(CASE WHEN Pay_ClassHrs = 'Bugeted_Work_Hrs' THEN Pay_ClassHrs END) AS x
, SUM(CASE WHEN Pay_ClassHrs = 'Bugeted_Benefit_Hrs' THEN Pay_ClassHrs END) AS x
, SUM(CASE WHEN Pay_Class$ = 'POT_$' THEN Pay_Class$ END) AS x
, SUM(CASE WHEN Pay_Class$ = 'PED_$' THEN Pay_Class$ END) AS x
, SUM(CASE WHEN Pay_Class$ = 'POR_$' THEN Pay_Class$ END) AS x
, SUM(CASE WHEN Pay_Class$ = 'Agency_$' THEN Pay_Class$ END) AS x
, SUM(CASE WHEN Pay_Class$ = 'PWH_$' THEN Pay_Class$ END) AS x
, SUM(CASE WHEN Pay_Class$ = 'Sick_$' THEN Pay_Class$ END) AS x
, SUM(CASE WHEN Pay_Class$ = 'PTO_$' THEN Pay_Class$ END) AS x
, SUM(CASE WHEN Pay_Class$ = 'Holiday_$' THEN Pay_Class$ END) AS x
, SUM(CASE WHEN Pay_Class$ = 'PJB_$' THEN Pay_Class$ END) AS x
, SUM(CASE WHEN Pay_Class$ = 'PNH_$' THEN Pay_Class$ END) AS x
, SUM(CASE WHEN Pay_Class$ = 'Bugeted_Work_$' THEN Pay_Class$ END) AS x
, SUM(CASE WHEN Pay_Class$ = 'Bugeted_Benefit_$' THEN Pay_Class$ END) AS x
FROM [#PremierThree]
GROUP BY
[Facility]
, [Job_Code]
未经测试!
full outer join
但它可能与更简单的
inner join
如果两个子查询产生相同的行(
在你的情况下,很可能使用临时表
).
SELECT
COALESCE(p1.Facility,p2.Facility) Facility
, COALESCE(p1.Job_Code,p2.Job_Code) Job_Code
, [PBS_Hrs], [POT_Hrs], [PED_Hrs], [POR_Hrs], [Agency_Hrs], [PWH_Hrs], [Sick_Hrs], [PTO_Hrs], [Holiday_Hrs], [PJB_Hrs], [Bugeted_Work_Hrs], [Bugeted_Benefit_Hrs]
, [PBS_$], [POT_$], [PED_$], [POR_$], [Agency_$], [PWH_$], [Sick_$], [PTO_$], [Holiday_$], [PJB_$], [PNH_$],[Bugeted_Work_$], [Bugeted_Benefit_$]
FROM (
SELECT
[Facility]
, [Job_Code]
, [PBS_Hrs], [POT_Hrs], [PED_Hrs], [POR_Hrs], [Agency_Hrs], [PWH_Hrs], [Sick_Hrs], [PTO_Hrs], [Holiday_Hrs], [PJB_Hrs], [Bugeted_Work_Hrs], [Bugeted_Benefit_Hrs]
FROM [#PremierThree]
PIVOT
(SUM(PayHours)
FOR [Pay_ClassHrs] IN ([PBS_Hrs], [POT_Hrs], [PED_Hrs], [POR_Hrs], [Agency_Hrs], [PWH_Hrs], [Sick_Hrs], [PTO_Hrs], [Holiday_Hrs], [PJB_Hrs], [Bugeted_Work_Hrs], [Bugeted_Benefit_Hrs])
) AS pvt1
) AS p1
FULL OUTER JOIN (
SELECT
[Facility]
, [Job_Code]
, [PBS_$], [POT_$], [PED_$], [POR_$], [Agency_$], [PWH_$], [Sick_$], [PTO_$], [Holiday_$], [PJB_$], [PNH_$],[Bugeted_Work_$], [Bugeted_Benefit_$]
PIVOT
(SUM(PayAmount)
FOR [Pay_Class$] in ([PBS_$], [POT_$], [PED_$], [POR_$], [Agency_$], [PWH_$], [Sick_$], [PTO_$], [Holiday_$], [PJB_$], [PNH_$],[Bugeted_Work_$], [Bugeted_Benefit_$])
) AS pvt2
) AS p2
ON p1.Facility = p2.Facility AND p1.Job_Code = p2.Job_Code
ORDER BY
[Facility], CAST([Job_Code] AS INT)
;
对于T-SQL:就我个人而言,即使使用连接方法,当pivot开始变得复杂时,我也看不到它有任何优势。