我不知道如何在一个查询中获得所有想要的结果,但最终使用了以下两个查询来满足我的要求:-
第一个查询
SELECT
pot.`id` AS `po_id`,
pot.`order_quantity` AS `po_order_quantity`,
pot.`applicable_approved_unit_rate` AS `po_unit_rate`,
pot.`applicable_sales_tax_rate` AS `po_tax_rate`,
pot.`is_open` AS `po_is_open`,
pot.`is_active` AS `po_is_active`,
st.`id` AS `sup_id`,
st.`name` AS `sup_name`,
SUM(dot.`quantity`) AS `total_ordered`
FROM `purchaseorder` pot
INNER JOIN `deliveryorder` dot ON (dot.`purchase_order_id` = pot.`id`)
INNER JOIN `approvedrate` art ON (pot.`approved_rate_id` = art.`id`)
INNER JOIN `supplier` st ON (art.`supplier_id` = st.`id`)
WHERE (
pot.`is_active` = 1
AND pot.`is_open` = 1
AND art.`material_id` = @materialid
AND art.`in_effect` = 1
AND art.`is_active` = 1
AND dot.`is_active` = 1
AND st.`is_active` = 1
)
HAVING pot.`order_quantity` >= `total_ordered` + @materialquantity
第二次查询
SELECT
pot.`id` AS `po_id`,
pot.`order_quantity` AS `po_order_quantity`,
pot.`applicable_approved_unit_rate` AS `po_unit_rate`,
pot.`applicable_sales_tax_rate` AS `po_tax_rate`,
pot.`is_open` AS `po_is_open`,
pot.`is_active` AS `po_is_active`,
st.`id` AS `sup_id`,
st.`name` AS `sup_name`,
0 AS `total_ordered`
FROM `purchaseorder` pot
INNER JOIN `approvedrate` art ON (pot.`approved_rate_id` = art.`id`)
INNER JOIN `supplier` st ON (art.`supplier_id` = st.`id`)
WHERE (
pot.`is_active` = 1
AND pot.`is_open` = 1
AND art.`material_id` = @materialid
AND art.`in_effect` = 1
AND art.`is_active` = 1
AND st.`is_active` = 1
AND pot.`order_quantity` >= @materialquantity
AND pot.`id` NOT IN
(
SELECT dot.`purchase_order_id`
FROM `deliveryorder` dot
WHERE dot.is_active = 1
)
)