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WPF:如何设置UserControl显示的对话框的所有者窗口?

user-controls dialog vb.net wpf .net

Zack Peterson · 技术社区 · 16 年前

我有一个WPF应用程序,有这三种类型的东西。。。

窗口主
用户控制扎克

<Window x:Class="WindowMain"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:local="clr-namespace:ProjectName"
        ...
        Name="WindowMain">
    <Grid>
        ...
        <local:UserControlZack x:Name="UserControlZack1" ... />
        ...
    </Grid>
</Window>

UserControlZack1显示一个WindowModal日志框。。。

Partial Public Class UserControlZack

   ...

    Private Sub SomeButton_Click(...)
        'instantiate the dialog box and open modally...
        Dim box As WindowModal = New WindowModal()
        box.Owner = ?????
        box.ShowDialog()
        'process data entered by user if dialog box is accepted...
        If (box.DialogResult.GetValueOrDefault = True) Then
            _SomeVar = box.SomeVar
            ...
        End If
    End Sub

End Class

box.Owner = Me.Owner

我不能用 box.Owner = Me.Parent ,因为它返回的是网格,而不是窗口。

我不能用 box.Owner = WindowMain ,因为“'WindowMain'是类型,不能用作表达式。”

6 回复 | 直到 9 年前

134

slavoo user3099232 10 年前

尝试使用

.Owner = Window.GetWindow(this)

Nir 16 年前

要获取控件所在的顶级窗口,假设存在一个:

(Window)PresentationSource.FromVisual(this).RootVisual

要获取主窗口:

Application.Current.MainWindow

slavoo user3099232 10 年前

MyWpfDialog dialog = new MyWpfDialog();

//remember, this is WinForms UserControl and its Handle property is
//actually IntPtr containing Win32 HWND.

new System.Windows.Interop.WindowInteropHelper(dialog).Owner = this.Handle;

dialog.ShowDialog();

Andrew Barrett 16 年前

更新尝试帮助格雷格从评论。该命令在windows主菜单、用户控件中的按钮和用户控件中的上下文菜单中工作。

public static class Commands
{
    public static RoutedUICommand TestShowDialogCommand = new RoutedUICommand("Test command", "TestShowDialog", typeof(Commands));
}

在您的主窗口中注册这些:(您不需要canshow它默认为true)

    public Window1()
    {
        InitializeComponent();

        CommandManager.RegisterClassCommandBinding(typeof(System.Windows.Controls.Control),
            new CommandBinding(Commands.TestShowDialogCommand, ShowDialogCommand, CanShowDialogCommand));
    }

    private void ShowDialogCommand(object sender, ExecutedRoutedEventArgs e)
    {
        var box = new Window();
        box.Owner = this;
        box.ShowDialog();

    }

    private void CanShowDialogCommand(object sender, CanExecuteRoutedEventArgs e)
    {
        e.CanExecute = true;
    }

这是主窗口的xaml:

<Window x:Class="WpfApplication1.Window1"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:WpfApplication1="clr-namespace:WpfApplication1"
Title="Window1" Height="300" Width="322">
<Grid>
    <StackPanel>
        <Menu>
            <MenuItem Header="Test">
                <MenuItem Header="ShowDialog" Command="{x:Static WpfApplication1:Commands.TestShowDialogCommand}"/>
            </MenuItem>
        </Menu>
        <WpfApplication1:BazUserControl />
    </StackPanel>
</Grid>
</Window>

这是我的用户控件的xaml(仅限默认代码隐藏)

<UserControl x:Class="WpfApplication1.BazUserControl"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:WpfApplication1="clr-namespace:WpfApplication1"
Height="300" Width="300">
<Grid>
    <StackPanel>
        <Button Command="{x:Static WpfApplication1:Commands.TestShowDialogCommand}" Content="ClickMe" ></Button>
        <TextBox>
            <TextBox.ContextMenu>
                <ContextMenu>
                    <MenuItem Header="ShowDialog" Command="{x:Static WpfApplication1:Commands.TestShowDialogCommand}" />
                </ContextMenu>
            </TextBox.ContextMenu>
        </TextBox>
    </StackPanel>
</Grid>
</UserControl>

您可以更进一步,改为在控制器类中处理命令,并使其更具MVC风格。

Zack Peterson 16 年前

我通过我的XAML一路爬回来让它工作。。。

box.Owner = DirectCast(DirectCast(DirectCast(Me.Parent, Grid).Parent, Grid).Parent, Window)

Davy8 16 年前

把窗口的名称改成WindowMain1或者别的什么,然后把所有者设置成那个名称怎么样?