从CSharp中的List获取HashSet和Dictionary,按嵌套属性分组

对不起,我是C#新手,我来自Java 8。

我在用C#检查代码,

在命名空间中 IBM.Watson.Assistant.v1.Model

public class LogCollection
{
    public LogCollection();
    public List<Log> Logs { get; set; }
    public LogPagination Pagination { get; set; }
}

在同一命名空间中,类:

班 Log

public class Log
{
    public Log();
    public MessageRequest Request { get; set; }
    public MessageResponse Response { get; set; }
    public string LogId { get; set; }
    public string RequestTimestamp { get; set; }
    public string ResponseTimestamp { get; set; }
    public string WorkspaceId { get; set; }
    public string Language { get; set; }
}

班 MessageResponse

public class MessageResponse
{
    public MessageResponse();
    public MessageInput Input { get; set; }
    public List<RuntimeIntent> Intents { get; set; }
    public List<RuntimeEntity> Entities { get; set; }
    public bool? AlternateIntents { get; set; }
    public Context Context { get; set; }
    public OutputData Output { get; set; }
    public virtual List<DialogNodeAction> Actions { get; }
}

和类 Context

public class Context : DynamicModel<object>
{
    public Context();
    public string ConversationId { get; set; }
    public Dictionary<string, object> System { get; set; }
    public MessageContextMetadata Metadata { get; set; }
}

现在我有了

List<IBM.Watson.Assistant.v1.Model.Log> listLog = logCollection.Logs;

我想弄清楚 ConversationId 进入HashSet(或获取 HashSet 从对象的嵌套属性 List ).

In Java 8 我会使用:

Set<String> setConversationId = listLog.stream()
    .map(log -> log.getResponse().getContext().getConversationId())
    .collect(Collectors.toSet());

在C#中,我可以做这样的事情吗?

HashSet<string> setConversationId = new HashSet<string>(listLog.HOW_TO_GET_ConversationId_FROM_Context_FROM_Response);

现在,我想按以下方式对日志进行分组 对话ID 在字典里。

Java 8是这样的:

public Map<String, List<Log>> getMapFromList(List<Log> listLog)
{
    Map<String, List<Log>> map = listLog
        .stream().collect(Collectors.groupingBy(
            log -> log.getResponse().getContext().getConversationId(), 
            Collectors.mapping(log -> log, Collectors.toList())
            ));
    return map;
}

在C#

public Dictionary<string, List<Log>> getDictionaryFromList(List<Log> listLog)
{
    Dictionary<string, List<Log>> dictionary = listLog
        .???????;
    return dictionary;
}

如何根据某个列表的嵌套属性将数据分组到字典中?

注: :我更喜欢functional/lambda而不是Linq响应。